Electronics Engineering

A welding transformer uses the alternating current supplied to the welding shop at a high voltage to produce the low voltage welding power

A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does

A: a transformer will follow the rule of input output ratio with no load. As soon as a load is applied there will be changes in the ratio

A: Depends on the circuitry involved an op amp normally has a 90 Db rejection from variation, Logic gates however are more sensitive to power supply variation for the simple point that triggering points changes which translate in false triggering and the circuits miss behaving

Most miscellaneous electronic components are used to accomplish or support the primary electronic functions of rectification, amplification, oscillation, and switching and timing.

An electrical current is passed through a cathode, which emits electrons. Next, a high voltage electrical source is powered on the other end of the x-ray tube, which makes the electrons move to the other side. The electrons then collide with an anode, which produces the photons that are needed to produce x-rays.

There is a company called Maxis who have brought programs like SimCity to the wider games world. The only other thing that fits the Maxi Computer description is a supercomputer on the US Defence Department could afford.

4.

a digital multimeter uses similar input circuits to those used in an analog multimeter for the various scales, but uses a dual slope integrating analog to digital converter to get a precise digital value of four or five digits to display. this type of analog to digital converter is slow but very precise, also though slow it is more than fast enough for a human to not perceive the slowness.

Electrical and Electronics Engineering

Current I = V/R

V = 9V

R = 100ohm

I = 9V/100ohm = 90mA

Basically durability.

These are a niche market, and the demand is not particularly high. Designing a Gunn or Impatt oscillator is not a trivial exercise, and the biasing is a pain. These designs are generally built by skilled craftsmen and are not suited to mass production. At 24 GHz or below, a GaAs MESFET or PHEMT is much more practical as an active device.

The term "absolute zero" is used for the minimal possible temperature (-273 K).

The term "relative zero" is not a term I know, but it could refer to the difference between two velocities, which are equal. In Physics, independent observers do not observe a velocity of the other if they are moving at the same speed (relative zero). <Feb 18, 2014 - Bruno>

electrical cable jointer for one year expreence

transformer max earth fault current

Yes. Let's look at an example.

A 12 volt system can operate a 12 volt relay coil to actuate the plunger. But when the field of the coil collapses in the instant following when the coil is de-energized, the collapsing field can generate an "inductive kick" that can easily reach several hundred volts.

Relay coils frequently have diodes across their coils to shunt this voltage through the coil and prevent it reaching other parts of the circuit because it is a higher voltage and could damage components.

As a closing note, you're not "getting something for nothing" or generating more energy out of the coil than originally went in. The power in still equals the power out (less any loss). With a properly designed coil utilizing Marko Rodin's configuration, losses are negligible.

y(n) = x(n) + x(n-1) + x(n-2)

A VAR Meter is used to measure Reactive Power in AC Circuits - Pure reactive components dissipate zero power, which makes sense in a DC circuit, as a capacitor passes no DC current and an inductor displaces no voltage. Yet, in an AC circuit, the reactive components "seem" to dissipate power, as current passes through the capacitor and the inductor sees a voltage drop. This counterfeit power is called "reactive power" and is measured not in Watts, but in VARs (Volt-Amps-Reactive). Its mathematical formula symbol is "Q".

A VAR Meter is used to measure Reactive Power in AC Circuits - Pure reactive components dissipate zero power, which makes sense in a DC circuit, as a capacitor passes no DC current and an inductor displaces no voltage. Yet, in an AC circuit, the reactive components "seem" to dissipate power, as current passes through the capacitor and the inductor sees a voltage drop. This counterfeit power is called "reactive power" and is measured not in Watts, but in VARs (Volt-Amps-Reactive). Its mathematical formula symbol is "Q".

Yes, they will. One can connect anything to anything else. Will it work? If so, how well? Is it safe? If the four speakers are connected in series, the total impedance of the speakers will be the sum of all the impedances of the speakers: 5.5 + 5.5 + 5.5 + 5.5 = 22 ohms The 22 ohm load on the amplifier will be a bit higher than the amp has been designed for, but the setup will work. At modest power levels it is doubtful that anything audible will be noticeable because of that slight mismatch, and as long as one doesn't crank it up too high, the amp won't notice the difference. It would be wise when hooking up the speakers to insure they are all hooked up in phase... Something important has to be added: There is really no 16 ohm amplifier on the market. The amplifier will have an output impedance of around 0.08 ohms. In hi-fi we have always impedance bridging. Zout << Zin. That means that the output impedance of the amplifier is much less than the input impedance of the loud speaker. The damping factor Df = Zin / Zout tells you what Zout is. Zout = Zin/Df. If the damping factor Df = 200 and the loudspeaker impedance is Zin = 16 ohms, the output impedance of the amplifier is Zout = 16 / 200 = 0.08 ohms. You see, there is no "16 ohm amplifier" with a 16 ohm output impedance. Scroll down to related links and look at "Voltage Bridging - Zout < Zin".

The rate at which work IS being done - or at which it would be done if you switched on an electrical appliance or some other piece of electrical equipment - is called 'power' and it is measured in watts.

yes

Voltage = (current) x (resistance)

Current = (voltage)/(resistance)

Resistance = (voltage)/(current)