Electronics Engineering

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A capacitor is passive like a resistor is passive it performs no active amplification.

By testing the C B E terminals.

Insufficient information, please ask the question

in a sensible clear way.

Assuming that at one time a positive potential exists on a anode then assign a [+] to that point follow this procedure for all diodes and resistors. You can calculate Boltzmann impedance of a diode but industry wise a .6v to.8v is standard practice for a diode drop since it follow an exponential curve. .6 volts is for low current and .8volts is for more current

Yes as long as both the 2450 mAh battery and 600 mAh battery have the same voltage. The larger one will just last longer and take longer to charge up (I am assuming these are the solar powered type lights).

There are several different high potential (hipot) tests, but they all generally involve applying a high voltage (high electrical potential) across something being tested to determine how good an insulator the material or substance is. A vacuum inside an enclosed space can insulate materials inside that space. To cite a single example, in a variable vacuum capacitor, a glass or ceramic "bottle" with a flexible metal bellows on one end contains a pair of plate sets. By expanding or compressing the bellows assembly, one set of plates can be moved closer to the other set, both of which are inside the vacuum "bottle" of the device. This changes the capacitance of the device, and thus allows it to be used to tune a circuit. If a hipot test were conducted across the plates of the capacitor, the integrity of the insulative properties of the vacuum enclosure could be tested. If air should have leaked inside, this air would be ionized by the high voltage and the hipot test would show this. This vacuum capacitor would be ineffective in a high voltage application, like the tuning of a high power radio transmission circuit.

They use transistor as the purpose to transfer the voltage

vineet nayyar

By the coloured rings around the resistor, look at the link below for detailed info

http://wiki.xtronics.com/index.php/Resistor_Codes

by "Aadil Razzak (Failed 4 times So Far)"

Yes.

A depletion region is formed when there is a junction of p and n type semiconductor impurities. As one moves across the junction from one end to the other, one sees a change in the free carrier density from naturally high on one side to naturally low on the other. It is true of both n and p type carriers in every juntion, albeit in opposite directions. This gradient of charges can create an avalanche of current except that it is counteracted by a strong electric field at the junction; the greater the gradient of mobile charges, the larger the electric field. The region of this electric field is called the depletion region because the free electric carriers are less dense in the region than they naturally occur. The loss of these carriers leaves charged semiconductor atoms in the region in their wake. By Coulomb's law, the total number of charged atoms required is fixed by the amount of electric field and the two are proportional. Hence, in a lightly doped semiconductor, the depth to which the electric field penetrates (i.e the depth of the depletion region) is larger because the density of charged atoms is low.

Voltage and current are actually inversely proportional to one another. The formula P=IV is what you need to look at here, where P is Power, V is voltage, and I is current. Rearranging the equation you will see that V = P/I. You can see that if you increase voltage, while holding power constant, current is reduced. Now, to your question. The losses on a transmission line are proportional to the current flowing on the line, so transmitting at high voltage (and hence low current) is beneficial as it reduces the amount of power that is lost due to resistance in the line itself.

Time domain basically means plotting a curve of amplitude over thr time axis.

A given function or signal can be converted between the time and frequency domains with a pair of mathematical operators called a transform. An example is the Fourier transform, which decomposes a function into the sum of a (potentially infinite) number of sine wave frequency components. The 'spectrum' of frequency components is the frequency domain representation of the signal. The inverse Fourier transform converts the frequency domain function back to a time function.

It depends on the resistance level in that area if the soil have low resistance then they will use high impedance system and vice versa..so reason behind this have to reduce fault current.

No. Unless the LED is specifically a laser, you can not make it focus like a laser by putting it in a housing. A laser produces coherent light, which is why it acts like a beam. A normal LED is not coherent, and you can not make it so. Although you can not make a collimated incoherent light beam able to travel similar distances as a collimated laser beam, you can collimate incoherent light into a beam which would travel some distance with a small amount of divergence.

The Loader is a program that moves the executable file produced by linker from the secondary storage device to memory for execution

The coulomb is an SI derived unit used to measure electric charge. It is a special name given to an 'ampere second', which are both SI base units.

the speakers are 8kOhm or 8000Ohm

This is known as a Coaxial DC power connector. http://en.wikipedia.org/wiki/Coaxial_DC_Power_Connectors

Amplitude Modulation and Frequency Modulation. They are different methods of transmitting radio signals. AM is good for transmitting radio signals long distance FM is good for transmitting radio signals short distances but better quality

The Z80's rotate-with-carry instructions, RRC and RLC, for Rotate Right and Rotate Left, are great for taking action based on individual bits being set or cleared. If you start with a clear carry flag, then get a byte from wherever, then you can rotate left or right one bit at a time. The bit you want to examine will eventually be in the carry. Then, execute a JP C, (location) or JP NC, (location) to jump based on whether or not the bit is set. (Of course, you could also use JR). The beauty of RLC and RRC is that they don't destroy the byte that you are using - after doing enough rotates, the byte will be as it was before.

Yes.... capacitors offer impedance to flow of ac current.. But since the value of impedance is inversly proportional to the frequency of source therefore the impedance offered generally is much lesser than in case of dc current

A resistor.