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Intel 8086 and 8088
The Intel 8086/8088 family of microprocessors is a 16 bit architecture on a 16 bit (8086) or an 8 bit (8088) bus. The 8088 was the processor in the original IBM PC, and has evolved into the most popular processor used today in PC's and servers.
1,056 Questions
Why tri-state device is useful in bus oriented system?
In a multiplexed bus system, many devices are connected to
a common bus. If 2 or more devices attempt to use the bus
at the same time , then data will be lost. Thus only one
one device must be allowed to use the bus at a time. One
method is to connect the devices through tri-state
devices , which when disabled will effectively disconnect
devices from the bus.
How many bits is the data bus for a 486dx4 processor?
A 386SX processor has 16-bits and 386DX has 32-bits
How many addressing mode of 8086 assembly language program?
there are five addressing modes in 8086
they are :
1->direct addressing
2->Indirect addressing
3->index addressing
4->immediate addressing
5->register addressing
How do you find HEX code in 8086 microprocessor?
There are many instructions in the 8085. To find the hex code for a particular instruction, you need to look at the data sheet. For more information, please see the Related Link below.
Which register in 8086 contains the address of the next instruction to be fetched?
program counter holds the address of the next instruction.
What is the reason for naming microprocessor as 8085 and microcontroller as 8051?
b/c the 8085 microprocessor is the first 8 bit microprocessor which Intel is produces in 1877 and this is the first general purpose 8 bit microprocessor.
there was an 8 bit general purpose register before 8085 named as 8008 but this microprocessor is not functional 8 bit microprocessor
Flags are used to indicate the status of various things, usually following some kind of operation. For instance, the ZERO flag indicates the result is zero, the CARRY flag indicates the operation results in a carry, the NEGATIVE flag indicates the result is negative, etc.
Flags can be used in loop control. For instance you can decrement a counter at the end of a loop, and jump conditionally to the top of the loop if the counter is non zero.
Where can you find an opcode sheet for 8085 microprocessor?
ACI n |CE|*****| 7|Add with Carry Immediate |A=A+n+CY |
|ADC r |8F|*****| 4|Add with Carry |A=A+r+CY(21X)|
|ADC M |8E|*****| 7|Add with Carry to Memory |A=A+[HL]+CY |
|ADD r |87|*****| 4|Add |A=A+r (20X)|
|ADD M |86|*****| 7|Add to Memory |A=A+[HL] |
|ADI n |C6|*****| 7|Add Immediate |A=A+n |
|ANA r |A7|****0| 4|AND Accumulator |A=A&r (24X)|
|ANA M |A6|****0| 7|AND Accumulator and Memory|A=A&[HL] |
|ANI n |E6|**0*0| 7|AND Immediate |A=A&n |
|CALL a |CD|-----|18|Call unconditional |-[SP]=PC,PC=a|
|CC a |DC|-----| 9|Call on Carry |If CY=1(18~s)|
|CM a |FC|-----| 9|Call on Minus |If S=1 (18~s)|
|CMA |2F|-----| 4|Complement Accumulator |A=~A |
|CMC |3F|----*| 4|Complement Carry |CY=~CY |
|CMP r |BF|*****| 4|Compare |A-r (27X)|
|CMP M |BF|*****| 7|Compare with Memory |A-[HL] |
|CNC a |D4|-----| 9|Call on No Carry |If CY=0(18~s)|
|CNZ a |C4|-----| 9|Call on No Zero |If Z=0 (18~s)|
|CP a |F4|-----| 9|Call on Plus |If S=0 (18~s)|
|CPE a |EC|-----| 9|Call on Parity Even |If P=1 (18~s)|
|CPI n |FE|*****| 7|Compare Immediate |A-n |
|CPO a |E4|-----| 9|Call on Parity Odd |If P=0 (18~s)|
|CZ a |CC|-----| 9|Call on Zero |If Z=1 (18~s)|
|DAA |27|*****| 4|Decimal Adjust Accumulator|A=BCD format |
|DAD B |09|----*|10|Double Add BC to HL |HL=HL+BC |
|DAD D |19|----*|10|Double Add DE to HL |HL=HL+DE |
|DAD H |29|----*|10|Double Add HL to HL |HL=HL+HL |
|DAD SP |39|----*|10|Double Add SP to HL |HL=HL+SP |
|DCR r |3D|****-| 4|Decrement |r=r-1 (0X5)|
|DCR M |35|****-|10|Decrement Memory |[HL]=[HL]-1 |
|DCX B |0B|-----| 6|Decrement BC |BC=BC-1 |
|DCX D |1B|-----| 6|Decrement DE |DE=DE-1 |
|DCX H |2B|-----| 6|Decrement HL |HL=HL-1 |
|DCX SP |3B|-----| 6|Decrement Stack Pointer |SP=SP-1 |
|DI |F3|-----| 4|Disable Interrupts | |
|EI |FB|-----| 4|Enable Interrupts | |
|HLT |76|-----| 5|Halt | |
|IN p |DB|-----|10|Input |A=[p] |
|INR r |3C|****-| 4|Increment |r=r+1 (0X4)|
|INR M |3C|****-|10|Increment Memory |[HL]=[HL]+1 |
|INX B |03|-----| 6|Increment BC |BC=BC+1 |
|INX D |13|-----| 6|Increment DE |DE=DE+1 |
|INX H |23|-----| 6|Increment HL |HL=HL+1 |
|INX SP |33|-----| 6|Increment Stack Pointer |SP=SP+1 |
|JMP a |C3|-----| 7|Jump unconditional |PC=a |
|JC a |DA|-----| 7|Jump on Carry |If CY=1(10~s)|
|JM a |FA|-----| 7|Jump on Minus |If S=1 (10~s)|
|JNC a |D2|-----| 7|Jump on No Carry |If CY=0(10~s)|
|JNZ a |C2|-----| 7|Jump on No Zero |If Z=0 (10~s)|
|JP a |F2|-----| 7|Jump on Plus |If S=0 (10~s)|
|JPE a |EA|-----| 7|Jump on Parity Even |If P=1 (10~s)|
|JPO a |E2|-----| 7|Jump on Parity Odd |If P=0 (10~s)|
|JZ a |CA|-----| 7|Jump on Zero |If Z=1 (10~s)|
|LDA a |3A|-----|13|Load Accumulator direct |A=[a] |
|LDAX B |0A|-----| 7|Load Accumulator indirect |A=[BC] |
|LDAX D |1A|-----| 7|Load Accumulator indirect |A=[DE] |
|LHLD a |2A|-----|16|Load HL Direct |HL=[a] |
|LXI B,nn |01|-----|10|Load Immediate BC |BC=nn |
|LXI D,nn |11|-----|10|Load Immediate DE |DE=nn |
|LXI H,nn |21|-----|10|Load Immediate HL |HL=nn |
|LXI SP,nn|31|-----|10|Load Immediate Stack Ptr |SP=nn |
|MOV r1,r2|7F|-----| 4|Move register to register |r1=r2 (1XX)|
|MOV M,r |77|-----| 7|Move register to Memory |[HL]=r (16X)|
|MOV r,M |7E|-----| 7|Move Memory to register |r=[HL] (1X6)|
|MVI r,n |3E|-----| 7|Move Immediate |r=n (0X6)|
|MVI M,n |36|-----|10|Move Immediate to Memory |[HL]=n |
|NOP |00|-----| 4|No Operation | |
|ORA r |B7|**0*0| 4|Inclusive OR Accumulator |A=Avr (26X)|
|ORA M |B6|**0*0| 7|Inclusive OR Accumulator |A=Av[HL] |
|ORI n |F6|**0*0| 7|Inclusive OR Immediate |A=Avn |
|OUT p |D3|-----|10|Output |[p]=A |
|PCHL |E9|-----| 6|Jump HL indirect |PC=[HL] |
|POP B |C1|-----|10|Pop BC |BC=[SP]+ |
|POP D |D1|-----|10|Pop DE |DE=[SP]+ |
|POP H |E1|-----|10|Pop HL |HL=[SP]+ |
|SUB r |97|*****| 4|Subtract |A=A-r (22X)|
|SUB M |96|*****| 7|Subtract Memory |A=A-[HL] |
|SUI n |D6|*****| 7|Subtract Immediate |A=A-n |
|XRA r |AF|**0*0| 4|Exclusive OR Accumulator |A=Axr (25X)|
|XRA M |AE|**0*0| 7|Exclusive OR Accumulator |A=Ax[HL] |
|XRI n |EE|**0*0| 7|Exclusive OR Immediate |A=Axn |
|XTHL |E3|-----|16|Exchange stack Top with HL|[SP]<->HL
|SBB r |9F|*****| 4|Subtract with Borrow |A=A-r-CY |
|SBB M |9E|*****| 7|Subtract with Borrow |A=A-[HL]-CY |
|SBI n |DE|*****| 7|Subtract with Borrow Immed|A=A-n-CY
What are general purpose computer registers?
Ans:- Register is synchronous circuit thus all flip-flops are controlled by a common clock line.
There is four type of Register:
(i) Serial input, serial output (SISO)
(ii) Parallel input, serial output(PISO)
(iii) Serial input, parallel output(SIPO)
(iv) Parallel input, parallel output(PIPO)
Answered by HAFIJUR RAHMAN
Nowgong College,KKHSOU(Assam)India
How many pins are present in 8085 and 8086 microprocessor?
There are 256 ports available in the 8085 microprocessor. The IN and OUT instructions have an 8-bit port number, and that is where the 256 comes from.
In order to use ports, the hardware addressing system must decode IO/M-. Some implementations don't do this, so they map IO addresses to memory addresses. In that case, you could say there are 65536 possible IO addresses, but that is not the same as ports, because ports are specific to the IN and OUT instructions.
The other "problem" with IN and OUT is that you cannot specify the address in a register, while you can do so with indirect memory addressing.
How many no of address lines required in 64kB memory?
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
Difference between microprocessor and instruction code?
difference between micro operation and microinstruction
Why do 8086 need two ground pins?
8086 has two ground pins because to make the pins count 40(even number(40) so that it fits perfectly in ic cabin). that's all there no specfic operation for the both grounds .both do same operation
How do you interface keyboard with 8086?
first connect the 8255 to the 8086 microprocessor and configure it using the CWR then connect the key board to the 8255
What does the word addressing mean?
To speak to, to direct to the attention of something, to deal with something, or to mark with a destination, as in addressing a letter.
A self-addressed envelope is an envelope with your address on the front of it in the MAIL TO area. If the ad/directions include SASE...this means self-addressed stamped envelope. In this case, you would include postage so the company/organization/person can mail your request to you.
What is the Maximum clock frequency of 8086 microprocessor?
that depends on the microcontroller. check the datasheet.
Can a Mac Mini that has a DVI output be connected to an HDTV with an HDMI input?
I have a Sony KDL-52XBR4 connected to my Mac-Mini via a DVI to HDMI cable and it works fine. All I did was change the resolution to get it working. I'm pretty sure is in the 1280x800 range (I'm moving and the TV is in transit so I can't check at the moment). BUT, it does work and I use it all the time to watch iTunes & surf on Safari to watch Hulu. There is one quirk, the MacMini will invert the colors periodically, but I found a script someone else wrote that resets the display settings.
What circumstances made the IBM PC so successful?
This may not be a complete answer to what you are looking for, but if I were to guess I would have to say that IBM's became so popular because of the fact that they are one of the most sturdiest computers ever made. IBM iswidely known for their standards in durability Even though the IBM PC's don't have all of the cosmetic wows of say an Apple they are usually more durable and therefor last longer.
IBM became commercially popular because it's corporate strategy was to ensure the customer received support and solutions for all their business problems. Typically the larger the "user", the faster the solution. IBM's massive organization, as compared to all it's competitors, was capable of solving any problem at any cost if it's management felt it to be necessary to maintain good customer relations. IBM's PC computers were not leading edge by any standards, however, they did establish the standards for compatibility of software and internal architecture. The PC actually created a dilemma for IBM since it had capability to run and off load applications from their "bread and butter" computers, the mainframes. This was diametrically apposed to their corporate marketing/selling strategy for years.You filed chapter 7 in California 6 years ago how long do you have to wait to refile in WA state?
Bankruptcy is a Federal matter, your State makes no differece.
Under the new bankruptcy law taking effect on October 17, 2005, Chapter 7 cannot be filed unless the debtor was discharged from the previous Chapter 7 or bankruptcy more than eight years ago. The debtor cannot file a Chapter 13 unless: (1) the debtor received a discharge under Chapter 7, 11 or 12 more than four years ago; or (2) the debtor received a discharge under Chapter 13 more than two years ago.
