addressing mode is used to form an instruction format.
What is the need for timing diagram in microprocessor?
The need for a timing diagram for a microprocessor is, primarily, to allow you to properly design the interface logic that will support the microprocessor.
You need to know what lines are used to execute various data transfers, what are the timing of those lines with respect to each other, and how the microprocessor expects the external logic to behave.
You can also use the timing diagram to understand how the microprocessor functions and, particularly, to know how long each instruction will take.
Write a program to subtract two 16 bit numbers in microprocessor 8086?
.code
main proc
mov ax,@data
mov ds,ax
lea dx,msg ;printing msg
mov ah,09h
int 21h
mov ax,x ;ax=x
mov bx,y ;bx=y
cmp ax,0 ;jump to l3 if ax is negtive
jb l3
cmp bx,0 ;jump to l6 if bx is negative
jb l6
cmp ax,bx ;if ax<bx,then jump to l1
jl l1
sub ax,bx ;else normal sub
mov diff,ax ;diff=result is stored
jmp l2
l1: ;iff (+)ax<(+)bx
neg bx ;bx=-bx
clc
add ax,bx
neg ax ;-ans=ans
mov diff,ax
mov dx,2dh ;print '-'
mov ah,02h
int 21h
jmp l2
l3: ;iff (-)ax
neg ax ;-ax=ax
cmp bx,0 ;jump to l4 if bx is negative
jb l4
clc
add ax,bx ;ax=(+)ax+(+)bx
mov ax,diff
mov dx,2dh ;print '-'
mov ah,02h
int 21h
jmp l2
l4: ;if (-)ax & (-)bx
neg bx ;-bx=bx
cmp ax,bx ;if ax>bx then jump to l5
jg l5
sub ax,bx ;else ax-bx
mov diff,ax
mov dx,2dh ;print '-'
mov ah,02h
int 21h
jmp l3
l5: ;if(-)ax>(-)bx
xchg ax,bx ;exchange ax and bx
sub ax,bx ;ax-bx
mov diff,ax ;ans is positive
jmp l2
l6: ;iff (-)bx
neg bx ;-bx=bx
add ax,bx ;ax-(-)bx
mov diff,ax ;ans will be positive
mov ah,4ch
int 21h
main endp
Can you add two registers directly in assembly language?
Yes, as long as one of them is the accumulator...
ADD BX
... adds BX to AX and leaves the result in AX.
How many memory locations can be addressed by a microprocessor with 14 address lines?
2^14 memory locations. In general for n-bit address bus, its 2^n
when conditional jump instruction is executed it has 10 m/c cycles bt when nt executed it has 7 m/c cycles....while unconditional jump instruction has 10 m/c cycles...
Why does 8085 microprocessor has 8 bit flag register when it has only 5 flags?
The 8085 microprocessor has an 8-bit flag register, even though it only has 5 flags, because all of the registers in the 8085 are 8-bit or 16-bit. In fact, the flags register is considered to be part of the accumulator, as one "register pair", for purposes of stack push/pop and interrupt call/return.
Be warned, however, that you should not attempt to change the state of bits stored on the stack and then pop'ing them into AF, because some of the three "unused" bits might be undocumented but actually used, or their meaning might change between different versions of the chip.
What is the pin diagram of ic U6430B?
1.ground 2.supply voltage 3.relay driver 4.c1 oscillator 5.r1 oscillator 6.supply voltsge 7.lamp failure detection 8.start input
What is bus cycle in a microprocessor?
Bus cycle is a single transaction between the main memory and the CPU.
If you were able to look inside a RAM stick, it would look like at spreadsheet. 8 columns across (8 bits) and billions of rows long depending on the side of the RAM. So 1 bit is 1 character, eight bits is a word or 1 byte.
What is the capacity of DRAM with twelve address lines?
Since DRAM uses address multiplexing(essentially each line accesses both columns and rows in memory) you need to take 2 to the 24th power to find your total capacity(basically doubling the number of address lines). In this case it would be 16,777,216.
What is the difference between microprocessors and CPUs?
Another Answer
The CPU (Central Processing Unit) is the core of any computer, while the microprocessor refers to the whole functional chip that is inserted into a motherboard. The CPU is the sub architecture of the microprocessor that interprets the program instructions and cascade triggers the sub-functions of each instruction.
What do you mean by multiplexing the bus?
If you have less no of data than the no of bits of data or address to b transfer Multiplexing mean to manage given busses in such a way that data or address can be transferred perfectly
What is meant by latching in microprocessors?
It is the time period in the clock cycle in which the signal on the bus must be the valid expected data. ie. The stable period of the data transmission that will then be loaded into the microprocessor as the actual data.
0 3 5
What is an explanation of the 8288 Bus controller?
inteT 8288 BUS CONTROLLER FOR iAPX 86, 88 PROCESSORS Bipolar Drive Capability Provides , The Intel"' 8288 Bus Controller is a 20-pin bipolar component for use with medium-to-large iAPX 86, 88 , ). ÂËN I Address Enable: AEN enables command outputs of the 8288 Bus Controller at least 115ns after , of two ways dependent on the mode of the 8288 Bus Controller. I/O Bus Mode - The 8288 is in the I/O , no arbitration is present. This mode allows one 8288 Bus Controller to handle two external busses. No ... OCR Scan
datasheet
7 pages,
239.68 Kb
multiprocessor 8089 intel 8288 bus generator 8288 8284 clock generator pin diagram of 8288 bus controller 8288 bus controller signal 8288 bus controller by intel intel 8288 bus controller intel 8288 8288 bus controller datasheet abstract
datasheet frame
Abstract: 8288 Bus Controller DISTINCTIVE CHARACTERISTICS g • Bipolar drive capability • Multi-master or I , OPTION Not Applicable c. DEVICE NUMBER/DESCRIPTION 8288 Bus Controller b. PACKAGE TYPE P = 20-Pin , HIGH. This mode allows one 8288 Bus Controller to handle two external buses. This allows the CPU to , , the 8288 functions in the I/O Bus mode. When LOW, the 828B functions in the System Bus mode. 12 AIOWC , to read a Cascade Address from a master Priority Interrupt Controller onto the data bus. PDEN (IOB ...
develop and test an assembly language to convert a two digit BCD number to binary