Oxidation Numbers

4

SnO32-


calculation can be done to find the unknown oxidation state of tin


let; X=Sn


because of the overall charge is -2, the equation must equal to -2


X + 3(oxidation no of oxygen)=-2


X + 3(-2)=-2
X + (-6) = -2
X = +4


So, the oxidation no for tin in SnO32- is +4


this calculation can be rechecked to confirm the answer by substituting +4 back in the equation;


(+4) + (-6) = -2


and here we go
the answer was correct

Assuming you mean Cl, with a lowercase L, which is chlorine:

As with all elements chlorine has an oxidation number of 0 in it's elemental form. In most of it's compounds its oxidation state is -1, but it can also exist in all oxidation states from -1 to +7 except for +2 and +6.

Nitrogen's oxidation number is -4.Carbon's oxidation number is +3.

The cyanide ion has -1 charge. Nitrogen is in -3 state. By balancing the charges: the oxidation number of carbon is +4.

The oxidation number of nickel in nickel nitrate is +2. In nickel nitrate, the nitrate ion has a charge of -1, and since the overall compound is neutral, the nickel ion must have an oxidation state of +2 to balance the charges.

The oxidation number of manganese depends on the particular compound in which manganese is present. The most common oxidation states are +2 as in MnCl2, + 4 as in MnO2, and + 7 as in potassium permanganate, KMnO4.

In KNO3 the oxidation number of potassium (K) is 1+, for nitrogen (N) it is 5+, and for each oxygen (O) it is 2-

Group 14 elements have an oxidation number of +4 in most compounds, as they typically lose four electrons to achieve a stable octet configuration. However, they can also exhibit oxidation numbers of +2 and +4 in some compounds depending on the specific chemical reaction.

The oxidation number of one chromium atom in potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2 and each potassium atom has an oxidation number of +1, so the overall charge of the compound is zero, making the oxidation number of chromium +6 to balance it out.

There many with +3 oxidation.Some are Al, Fe, Bi.

+1 for each Na

-1 for oxygen (as it is peroxide)

The oxidation number of sulfur (S) in Na2S is -2. In Na2S, there are two Na+ ions with a charge of +1 each, making a total of +2. Since the compound is neutral, the oxidation number of sulfur must be -2 to balance out the charges.

Krypton is an inert gas.

-1 for each Cl, +2 for Sn

Usually yes, but they could be mixtures of atoms.

P= -4

Formulas for compounds

Li = +1; Al = +3; F = -1

but I think your formula is wrong Li3AlF6

4, 6, 8, 12, 16, 24, 48

Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat.

CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat

The number of valence electrons determine the chemical properties of a particular element. For example, elements in group 1 tend to donate its valence electron away to produce its stable +1 ion. It also explains the formation of -1 ions from group 17 elements (halogens).

-1.

A salt of the metal. It could be an oxide but equally, it could be a halide, carbonate, suplhate or other salt.

corrosion (in iron this is called rusting)

Type your answer here... you tell me the number

In the carbonate CO32- the sum of the oxidation numbers is the ionic charge (true for all poyatomic ions) O is assigned -2 so C has +4. (maths 4 +(-6) = -2)