Probability

1. He takes 6 steps forward and 5 steps backward

2. He takes 5 steps forward and 6 steps backward

consider 1:

p1 = (11C6)(0.4)^6*(0.6)^5

for 2:

p2 = 11C5(0.4)^5*(0.6)^6

total probability = p1 + p2

There are 13 clubs (including the seven of clubs), and 3 other sevens (from the other suits). So that makes 16 cards that are clubs or sevens. Thus, the probability of drawing a club or a seven from a standard 52 card deck is 16/52 = 4/13 (about 31%).

That depends on how many sides the cube has but if it was a 6 sided cube then the probability of getting a four is 1 to 6 and even is 3 to 6.

Since 4 is even, then the result set of 4 intersect with the result set of even, so the probability of rolling a 4 or an even number is 1 in 2, or 0.5.

Yes.

50%

Correct.

You probably have to reset.. I don't know why you woudntmarry though

Roughly speaking, one in 49000 chances.

- Bdx

24 ways.

The answer depends, among other factors, on what your occupation is and where in the world you live. For most people, the probability is negligible.

41 (13 + 13 + 13 + 2)

34.1% with the normal distribution.

The theoretical probability is 1. Lots of people have done it in the course of their lives so it is an event that has happened and will happen again.

There are twenty odd cards in a deck of cards. This is a math problem.

I was told by my doctor, that the chances of having multiples is very likely once you've conceived multiples in the past. And if you have multiples, they will skip a generation and then their kids will likely have multiples. Pretty cool.

Ancient Olympic Games were extended from a one day festival with a few events to a five day event with wrestling, boxing, horse racing, jumping, javelin, and chariot racing.

one in 100 or 10in a 1000

its 50/50

You want: P(even) * P(even) * P(even) * P(even). P(even) = 3/6 or 1/2. Therefore probability even on 4 rolls is: 1/2 * 1/2 * 1/2 * 1/2 = 1/16 = 0.0625.

It is 6!/66 = 720/66 = 0.0154 approx.

They are both measures of the probability of an event occurring.

ask one

In the sample space [1,20], there are 8 prime numbers, [2,3,5,7,11,13,17,19]. The probability, then, of randomly choosing a prime number in the sample space [1,20] is (8 in 20), or (2 in 5), or 0.4. The probability of choosing two of them is (8 in 20) times (7 in 19) which is (56 in 1064) or (7 in 133) or about 0.05263.

The fundamental concept is that there are many processes in the world that contain a random element. If that were not the case, everything would be deterministic and there would be no need for probability of statistics.

2 in 7.