C Programming

ADT stands for abstract data type. It is basically a set of data values and associated operations that are specifically independent in nature. Examples of adt are stacks,trees,lists(doubly,circular,etc) and so on. Class is a user defined data type which the user can use in implementing a stack ADT or tree ADT. Class is used for implementation as it provides data hiding and encapsulation which are the features of ADT in object oriented programming. Hope this helps!

A proposition is a statement that is either true or false (its "truth value"). Example of a proposition: Belgium is a country in Europe. A predicate is a proposition whose truth depends on the value of one or more variables. Example of a predicate: x is a country in Europe. In this example, x is the variable, and the statement is true or false depending on what is chosen for x. For x=Belgium, the statement is true; for x=Egypt, it's false.

A predicate with one variable can be seen as a property, that is true or false of something, where the something is left open. A predicate with two (or more) variables can be seen as a relation between things, where the things are left open.

A machine is merely something that performs or assists in performing a task.

The simplest examples of machines are levers, pulleys, and wedges, all of which have probably been around in some form or another since before recorded history. So, I suppose no one really knows how they developed.

c++

O(1)

BINGO

Operators are a specific type of function that perform actions on operands, often involving mathematical or logical manipulation. Unlike general functions, which can simply map inputs to outputs, operators typically denote an operation (such as addition, subtraction, or logical conjunction) and can be unary (taking one operand) or binary (taking two operands). Additionally, operators often have specific syntax and precedence rules that dictate how they interact with each other in expressions.

You should have a separate variable to count each of those:

long nline, int npunct, nspace, ndigits;

...

printf ("%ld %ld %ld %ld\n", nline, int npunct, nspace, ndigits);

It is not the function but the compiler or interpreter which interprets the code. When the program is compiled and run the compiler checks the entire code line by line to check which function is called. If you encounter polymorphism in other Object Oriented Languages it would be more clear how a function with same name and different arguments are called.

// returns the minimum value in ns - iterative

public static final int findMinIterative(final int[] ns) {

if (ns.length == 0) {

return 0; // return 0 if ns is an empty array

}

// search each element of ns

int min = ns[0];

for (int i = 0; i < ns.length; ++i) {

// if an element smaller than min is found, store that as the new min

if (ns[i] < min) {

min = ns[i];

}

}

return min;

}

// returns the minimum value in ns - recursive

// Note that this problem does not lend itself to recursion; the solution is very similar to the iterative approach

public static final int findMinRecursive(final int[] ns) {

if (ns.length == 0) {

return 0; // return 0 if ns is an empty array

}

// start recursion

return findMinRecursive(0, ns[0], ns);

}

// recursive part of algorithm

private static final int findMinRecursive(final int i, final int min, final int[] ns) {

// bounds check

if (i >= ns.length) {

return min;

}

// recurse on next value of ns

return findMinRecursive(i + 1, Math.min(min, ns[i]), ns);

}

Is the materials that is being taught to employees don't not line up employees schedule

void main ()

{

int no1, sum, n;

clrscr()

sum = 0;

n = 1;

printf("\n enter the number to which sum is to be generated");

scanf("%d",&no1);

while(n<=no1)

{

sum=sum+n;

n=n+1

}

printf("\n the sum of %d = %d, no1, sum");

getch ();

}

Yes

A loop in a protein refers to a flexible segment of the polypeptide chain that connects two secondary structure elements, such as alpha helices or beta sheets. Unlike the more rigid structures, loops can vary in length and conformation, allowing proteins to adopt diverse shapes and functions. They often play critical roles in protein-protein interactions, enzyme activity, and binding sites for ligands. Loops are essential for the dynamic nature of protein structure and function.

If you had an array int numbers[10]; you would do it like this:

CODE:

int lowestnumber = numbers[0];

for(int i = 0; i < 10; i++){

if(numbers[i] < lowestnumber)

lowestnumber = numbers[i];

}

END CODE

I think this should work, and in the end the variable lowestnumber will hold the lowest value in the ten.

Hope this helps.

#include<stdio.h> #include<conio.h> void main() { clrscr(); int m[10][10]; int i,j,r,c; for (i=0;i<10;i++) { for (j=0;j<10;j++) { m[i][j]=0; } } printf("\n Enter size of row and colomn:"); scanf("%d %d",&r,&c); printf("\n Enter the two matrices: \n"); for (i=0;i<r;i++) { for (j=0;j<c;j++) { printf("Enter element %d %d of m1: ",(i+1),(j+1)); scanf("%d",&m[i][j]); } } printf("\n The matrix is: \n"); for (i=0;i<r;i++) { for (j=0;j<c;j++) { printf("%d ",m[i][j]); } printf("\n"); } printf("\n The transpose of the matrix is: \n"); for (i=0;i<r;i++) { for (j=0;j<c;j++) { printf("%d ",m[j][i]); } printf("\n"); } getch(); }

Yes there is, as a matter of fact. The most commonly known Friesian is the Holstien-Friesian diary cow. There are several different types: British, Dutch, German, Danish, Italian, Argentinian, Polish and Swedish. There also exists the American Beef Friesian.

The second Friesian is the Friesian horse, and there are also Friesian sheep.

It used to be a good question 30 years ago.

Right know you don't have to know anything about near and far pointers; but if you still use a 16-bit compiler, select 'Large Model' (or 'Huge Model'), and forget 'near' and 'far'

All operators must return a value, and it is this return value (the evaluation of the operation) that differentiates the pre-increment and post-increment operators. If the return value is of no concern, then the pre-increment operator is the preferred version, particularly when working with objects. This is because the post-increment operator's implementation will generally make a copy of the original object which it will return after incrementing the original object. If the return value is of no concern, then making a copy adds an expensive overhead (this doesn't apply to primitive data types since CPU optimisation can pre-empt the return value without requiring a copy to be made).

Applications for post-increment and pre-increment are many and varied, but ultimately the goal is to increment the value. Whether you use post-increment or pre-increment is largely down to whether you need to use the return value or not, and whether you need to use the original value or the incremented value.

Although the same thing can be achieved with longhand code, it is more efficient to use the appropriate post-increment or pre-increment operators.

For instance:

int x=1;

int y=x;

++x;

Can be implemented more efficiently with:

int x=1;

int y= x++;

Whereas:

int x=1;

++x;

int y=x;

Can be implemented more efficiently with:

int x=1;

int y= ++x;

Use caution when pre-incrementing the same value in a compound statement. For example:

int x=0;

int y= ++x * ++x;

The expected result is 2, but the actual result is 4. This is because both expressions (++x) return the same value: a reference to x. And since x is incremented twice, the expression evaluates to 2*2, not 1*2.

To get the expected result of 2, each operation must be evaluated separately:

int x=0;

int y= ++x;

y*= ++x;

/* Write a function that will scan a character string passed as an argument & convert all lowercase characters into their uppercase characters*/

#include<stdio.h>

#include<conio.h>

#include<string.h>

#include<ctype.h>

int str_upp(char c[])

{

int i;

char x;

printf("\n \n");

for(i=0;i<strlen(c);i++)

{

x=toupper(c[i]);

printf("%c",x);

}

return (0);

}

void main()

{

char c[10];

clrscr();

printf("Enter string : \n");

scanf("%s",c);

str_upp(c) ;

getch();

}

/*

Output:

Enter string :

Heloo

HELOO

*/

which r the first 10 amstrong numbers??

no

int x, *px, **ppx, ***pppx;

px = &x;

ppx = &px;

pppx = &ppx;

***pppx= 12345;

Move the print out requesting the user to enter an integer outside of the for loop and it will only print once instead of each time around the loop.

You'll need a way to save the even and odd numbers that you detect in the loop.

One way is to have separate arrays to hold the even and the odd numbers as you go around the loop. Then at the end of the loop you can have more loops to print the contents of one array and then the contents of the other array.

Another way is to concatenate the number onto separate Strings (even and odd) to be displayed after the data gathering loop.