To find the resistance in a circuit, use the equation R = V/I, where R is the resistence in ohms, V is the voltage, and I is the current in amps. Therefore, your equation is R = 120/0.6. Therefore, the resistance is 200 ohms.
Hope this helps
What is the effect of frequency on calibration of thermocouple?
the frequecy effect arises because of various factors such as:
1. Skin effect.
2. non uniform distribution of current along the heater wires.
3. spurious capative currents.
The transmit frequency is 140.250 MHz what is the best choice for the receive frequency?
Try 140.250Mhz. There should not be any shift from sent to received.
What is the net charge on a n-type or a p-type substance?
There is no net charge on either substance. However, an N type substrate contains atoms (such as arsenic or phosphorous) trapped in its lattice that have an electron (called a donor electron) in the outer (valence) band of electrons, which can be easily removed by a relatively weak electromotive force (voltage). A P type substrate, although electrically neutral, contains an element (such as boron) which has one fewer electrons in its valence band that it would like to have, making it an acceptor. The missing electron is often called a "hole". To elaborate slightly, bands of electrons like to have a certain number of electrons to be "stable". A donor atom may have one, or perhaps five, electrons in its valence band, while an acceptor might have three or seven. Both would be happier with zero or four or eight. When an N and a P type substance are in contact, a negative voltage on the N material with respect to the P material will allow electrons to move from the donor material to the vacant holes in the acceptor. If the voltage is applied in reverse, the negative charge on the P material attracts the holes away from the junction, and the (relatively) positive charge on the N material attracts electrons away from the junction, and very little current flows.
How many volts can a landline telephone handle without blowing?
Since the ringer voltage across the twisted pair is 120 VAC RMS the telephone can definitely handle that. Given the fact that the telephone is also supposed to survive induced surges from nearby lightning strikes to the line the telephone should be able to handle over 1000 V common mode impulses (but I don't know the exact limit). No telephone is expected to survive a direct lightning strike to the line (which could be millions of volts).
Note: common mode means the voltage is applied between the twisted pair lines (both at about the same voltage) and ground. If the survivable common mode voltage were to be applied across the twisted pair instead it would severely damage the telephone.
Name three of the best conductive materials.?
Leaving aside superconductors: graphene, silver, copper.
---- The D flip-flop tracks the input, making transitions with match those of the input D. The D stands for "data"; this flip-flop stores the value that is on the data line. It can be thought of as a basic memory cell. A D flip-flop can be made from a set/reset flip-flop by tying the set to the reset through an inverter. The result may be clocked. ----
What is the purpose of delay line in cro?
the delay line is used to delay the incoming signal vertical information and synchorized it with the horizontal
Can I connect two 4 ohm speakers and a 8 ohm speaker?
I depends on "how" you are connecting them. If you connected the 4 ohm speakers in series (positive terminal of one to the negative terminal of the other). This will leave a negative terminal of one unconnected and a positive terminal of the other unconnected. then connect them in parallel (the unconnected positive terminal of the 4 ohm speakers to the positive terminal of the 8 ohm speaker and the unconnected negative terminal of the other 4 ohm speaker to the negative terminal of the 8 ohm speaker. This will produce an overall 4 ohm load for 1 channel (assuming you are connecting to a stereo)
Or if you are connecting to a stereo with two 8 ohm outputs. Connect the 8 ohm to one channel then connect the above mentioned series connected 4 ohm speakers to the other channel for a total load of 8 ohms on both channels.
Parallel connections will equal less than the individual speaker load. The formula for this is: R X R/R + R where R is ohms for each speaker ie. Two 8 ohm speakers in parallel would be 8 x 8 (64)/ 8 + 8 (16) which is 4 ohms.
Series connections you just add them together ie. Two 8 ohm speakers in series would be 8 + 8 or 16 ohms.
FYI. If you measure the speakers with an ohmmeter it will be less than what it says on the speakers.
Speakers are measured in "impedance" which takes into account "reactance". The resistance of the speaker coil will change slightly with different frequencies applied so an 8 ohm speaker may read as 5-7 ohms (more or less) with an ohmmeter. A 4 ohm may read as low as 2.5 ohms on the same meter.
Some output transformers can handle half the ohms but it is always safer, as a general rule, to go "up" in speaker impedance without any damage. It's not wise to vary any with a system with solid state (transistor or IC) output coupling.
Hope I didn't get too technical. There is lots of good info on the internet about speaker configurations.
What is US voltage and Ecuador voltage?
US Voltage is 120 V @ 60 Hz.
Ecuador Voltage is 120 V @ 60 Hz.
They're compatible, the plugs are also the same.
Relationship between field current speed and induced voltage in excited dc generator?
The equation is
Ea = PNw(phi)/(pi) (see formated at http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&eq=E_a%3D\frac{PNw\phi}{\pi})
where Ea is the induced voltage, P the number of poles of the machine, w the electric frequency in rad/s, (phi) the magnetic flux.
referecen:
A. E. Fitzgerald et. al. Electric Machinery, 6th edition. McGraw-Hill.
No, there's no such thing as "digital energy". The calculator simply uses electrical energy. However, electronic equipment that are plugged into the electrical outlet (including calculators, radio receivers, computers, and many more) need special adapters to adapt the electrical current as follows:
1. The voltage from the outlet, 110 or 220 volt, is way too high. Electronic equipment usually needs voltages somewhere around 3-12 volts. A simple transformer would do, but:
2. The voltage for electronic appliances has to be DC. Since the electricity from the outlet is AC, that has to be converted too.
No, there's no such thing as "digital energy". The calculator simply uses electrical energy. However, electronic equipment that are plugged into the electrical outlet (including calculators, radio receivers, computers, and many more) need special adapters to adapt the electrical current as follows:
1. The voltage from the outlet, 110 or 220 volt, is way too high. Electronic equipment usually needs voltages somewhere around 3-12 volts. A simple transformer would do, but:
2. The voltage for electronic appliances has to be DC. Since the electricity from the outlet is AC, that has to be converted too.
No, there's no such thing as "digital energy". The calculator simply uses electrical energy. However, electronic equipment that are plugged into the electrical outlet (including calculators, radio receivers, computers, and many more) need special adapters to adapt the electrical current as follows:
1. The voltage from the outlet, 110 or 220 volt, is way too high. Electronic equipment usually needs voltages somewhere around 3-12 volts. A simple transformer would do, but:
2. The voltage for electronic appliances has to be DC. Since the electricity from the outlet is AC, that has to be converted too.
No, there's no such thing as "digital energy". The calculator simply uses electrical energy. However, electronic equipment that are plugged into the electrical outlet (including calculators, radio receivers, computers, and many more) need special adapters to adapt the electrical current as follows:
1. The voltage from the outlet, 110 or 220 volt, is way too high. Electronic equipment usually needs voltages somewhere around 3-12 volts. A simple transformer would do, but:
2. The voltage for electronic appliances has to be DC. Since the electricity from the outlet is AC, that has to be converted too.
Circuit of soft switching technique using zvzct in buck converter?
yes, zvzct is used to reduce the power dissipation and improve the efficiency of the circuit
How can you make a LED light up on only one 1.2 volt battery?
A: WELL you cannot not with 1,2v most LED start emitting at 1.8 v some as high as 5 volts . two need at least two 1.2 volts better is 9 volts then there is a problem voltage wise but the problem is now that you need a limiting resistor to ensure at least 10ma of current
How can you get the largest voltage difference?
There is no such thing as a 'voltage difference'! 'Voltage' means 'potential difference', so what you appear to be asking is "How do you get the largest potential difference difference?'!
Potential difference is caused by the separation of charges between two points. The greater the amount of charge separation, the greater the potential difference.
What are the advantages of series circuit?
The advantage of series is it uses less current than parallel
It depends on the periodic time of the supply which, in turn, is determined by the supply frequency. So, work out the periodic time of a 50 or 60-Hz waveform, and go from there.
If current is 3 amperes and resistance is 1.5 ohms, then voltage is 4.5 volts. (Ohm's law: voltage equals amperes times resistance) Power is volts times amperes, or 13.5 watts. A watt is a joule per second, so suppling 13.5 watts for 4.5 seconds produces 60.75 joules.
Your close, It's called a Wire Wound resistor. There are several types of resistors in use for electronics, the type is determined by it's construction.
A Carbon Comp. resistor is made up of .... you guessed it, carbon composition material which resists the flow of electrons, like blowing through different sized screens.
Film resistors work the same way, but they use a semiconducting film instead of a formed solid material.
Wire Wound resistors are actually 1 solid core wire wound around a ceramic rod.
In audio applications, a wire wound is the least detrimental to the sound, then film and composition. Wire wounds are the most expensive and get very large with high wattage values.
Here's a good link: http:/wwwzperiodzwelwynzhyphenzttzperiodzcozperiodzuk/pdf/application_notes/CCR_AN_Azperiodzpdf
What extracts the intelligence from a high frequency carrier in FM receivers?
One method to extract the intelligence (signal) from a high frequency carrier in FM receivers is with a phase locked loop.