Current = (voltage) / (resistance) = 110/20 = 5.5
The current will be 5.5 Amperes RMS, alternating at 50 Hz.
Note:
If you try this at home, you must use a gigantic "power" resistor.
The resistor dissipates E2/R = I2R = 605 watts RMS !
What makes an electric current?
An electric current is the movement of the conduction band electron "gas" in a conductor. This can be induced in various ways:
0.81 APEX
What are the condition for oscillation?
There are three conditions. These include positive feedback, the phase near the circuit needs to be either 36 or zero degrees, and the loop gain should be equal or greater than 1.
What is the amplification capacity of a typical transistor?
typically the amplification of a transistor 100 times.
What happens when a part of a parallel circuit is disconnected?
current decreases and resistance increases
How do you measure ac voltage by using galvanometer?
First rectify the voltage signal then pass it through galvanometer. its reading will give the rms value, so multipy it with form factor to get amplitude of the signal. Form factor for sinusoidal half wave and full wave are 1.11 and 2.22 respectively. One should also take care of voltage drop accross the rectifier diodes in calculation.
Increases
Can a transistor base emitter junction be used as zener diodes?
No, the doping profile is entirely wrong. Also some transistors have very low reverse breakdown voltage on the BE junction and will burn out!
How velocity modulation is different from normal modulation?
As we know normal modulation is superimposing the wave with another carrier signal but the concept of velocity modulation is totally different, as The modulation in velocity of a beam of electrons or ions caused by passing the beam through a high-frequency electric field, as in a cavity resonator there is no concept of superimposition.
Why bentley Nevada use negative voltage in proximitor?
Thanks to a bit of research performed by Sir Humphry Davy for the British Navy, we have a technology known as "cathodic protection." First developed to keep the copper hulls of British naval ships from corroding, this technology has been applied to protecting everything from oilrigs to gas pipelines to telephony cabinets. By keeping the cabinet frame at a more positive voltage than ground, corrosion is reduced and the life of the equipment is increased. Who would have guessed?
Yes, you could. The Geiger-Müller tube itself is fairly immune to electromagnetic fields by virtue of its construction. It's built inside a metal cylinder, which will offer some shielding. But outside the tube, things are different. Electromagnetic fields will deflect any charged particle (like a beta particle) that attempts to move through them. The amount and direction of the deflection of charged particles that move through a magnetic field will vary as a function of the direction of the magnetic lines of force relative to the path of the particle, the strength of the magnetic field, and the polarity and strength of the charge on the particle. Beta particles are high energy electrons, or sometime positrons, and the two particles will be affected oppositely by force on them created by their relative motion through the magnetic field. The term relative motion is important because it means the particle is moving in some way "across" or "through" the magnetic lines of force, and not "along" or "parallel" with them. Our beta particles, as they are generated and begin to move toward the GM tube, will encounter "diversion force" which will deflect them away from the original path of travel. This will affect their ability to actually get into the detector (the GM tube) through the window in it. And that will affect the count. It is improbable that looking for beta (or any charged) particles in a modest magnetic field will permit an accurate reading, and the reading will be "too low" because a number of the particles will be deflected away from the window of the GM tube. There is one more thing, and that's that it's hard for particles moving in an arc (along a curved course) to "hit a window" like the one in the GM tube and go in very far. Even if they get in the window, they will "curve across" the inside of the tube very near the window, and this might not allow them to trigger a current avalanche to record a "click" or a "count" for that particle. Readings could easily be very low if the detector is being used in a fairly stiff magnetic field. A link can be found below.
A rectifier is a device that is used to "change" (rectify) some kind of alternating current (AC) into direct current (DC). There is more to the story, but basically the rectifier is a "one-way" device that will permit current to flow though it in only one direction. That way one or more of these devices can be used in different curcuit configurations to change an AC input into a DC output.
What causes inductance in a circuit?
Transformers........ you can make coil with few turns to produce required inductance.
Advantages of negative feedback amplifier?
Most practical amplifier circuits use negative feedback for the following practical benefits: Stabilization of voltage gain, decreasing output impedance, increasing input impedance, decreasing distortion, increasing bandwidth.
How much energy do wind turbines create?
Two 5MW offshore wind turbines were built on the DEWI-OCC test field in Cuxhaven, Germany in December 2006.
A:Typically a wind turbine will produce between 5 and 8% of what they are rated for on average. Thus a 5 MWh plant should be able to produce 100,000 KWh each hour they are running. Most currently built systems are rated for 1 MWh in the United States so they typically will produce about 20,000 KWh of actual power. Wind systems are rated for average winds of 28 mph. If the average wind is 14 mph, they produce 10% of rated. If wind goes over 31 mph they produce no power and can consume energy to slow the blades. Feathering of blades does asist on reducing these issues, but doesn't eliminate them. A:A wind turbine in optimal winds generates its plate capacity. For example, a typical 3 MW wind turbine will generate 3 MW of electricity. An outdated but still moderately useful rule-of-thumb was that a megawatt would power a thousand homes; consumption is higher now so it's a little less than that, but still, a single 3 megawatt wind turbine will provide power in optimal winds to power close to 3000 homes.Winds vary, however. A typical jurisdiction will see 30% on average of the plate capacity over the course of a year. Some jurisdictions, such as north-eastern Brazil, have excellent winds and see capacity factors of 50%. Wind turbines are very economically viable at 30% capacity factors and become more profitable at higher factors.
Except in very low or very high winds, wind turbines will usually be generating some electricity. They aren't just on or off.
These factors are taken into account by grid managers when planning and managing new generation, new transmission and operating the grid.
Most industrial wind turbines do take about their faceplate capacity from the grid for a few minutes at startup to get the rotors moving. This is trivial in comparison to hours, days or even weeks of continuous generation. In addition, as one wind turbine in a farm comes on line, it provides power to the very local grid to be used by the other wind turbines; the wind farm will typically boot itself up with significantly less than the number of wind turbines times the faceplate capacity from other sources.
A:Every wind turbine has a range of wind speeds, typically 30 to 55 mph, in which it will produce at its rated, or maximum, capacity. If the wind is in the ideal range for a 1.5-MW wind turbine, it will produce power at the rate of 1.5 MW, its rated, or maximum, capacity.At slower wind speeds, however, the production falls off dramatically. Industry estimates project an annual output of 30-40%, but real-world experience shows that annual outputs of 15-30% of capacity are typical.
Answer
There is a hard rock band called AC/DC .
In electrical jargon, AC is short for alternating current and DC is short for Direct current.
How do you control a robot with a computer using infrared?
The same way that a Remote Control device can control, for instance, a TV. There needs to be at least a transmitter at one end and an equivalent receiver at the other end, or a suitable combination of both, for effective control/communication to occur. you could get infra-red kits that interface to your computer through one of the available ports (Serial, parallel, USB, P/S2, etc.) and have a wireless component that could be embedded within your "robot"'s electronics, thus giving you a connectivity between the computer and robot.
Why limit the amount of electricity passing trough a circuit?
Circuits are limited for a few reasons firstly because certain size wiring can only handle so much voltage and amperage before it could fail secondly wiring heats up when more amperage is drawn through it which can create fires or burning out of the circuit most appliances draw set amount of current and amperage if you have a low amperage appliance Eg pool pump drawing 4 amps and the windings start to fail the motor can start drawing excessive amperage creating a hazard, if you had a large circuit it may never trip the breaker indicating a fault with the appliance which can cause catastrophic failure.
Examples of the open loop system?
The system without feedback is known as open loop system. The examples of the open loop system are bread toaster, oven ,washing machine. The open loop systems are inaccurate & less complex.
How LCR-Q meter differs from digital multimer?
multimeters generally measure volts Kohms milliamps VOM
LCR meters measure inductance capacitance and resistance
Q requires 2 at once and probably a frequency range you may care about