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Gravity
One of the four fundamental interactions, gravity is responsible for the fact that any objects with mass attract one another. According to general relativity, it is a space time curvature, but according to quantum mechanics it is the result of exchanges of virtual gravitons.
4,784 Questions
What is the difference of gravitational pull on earth and mars?
Essentially, mass = gravity
Earth = 9.3 * mass of mars, standing at the same distance from both, earth would effect a force on you 9.3 times that of mars.
Surface gravity comparison:
weight of 100 kg on earth surface = 37.8 kg on mars surface
Yes
Who was responsible for the laws of gravity?
Sir Isaac Newton is the recognized founder of the Law of Gravity.
What does 5 gravity feel like?
heavy
When aircraft pilots make very tight turns or loop-the-loop they experience what is called G-force which is compared to the force of gravity which normally exists on earth, and is called "weight".
The force of gravity on Earth is G1, but those pilots can experience G5 or more. If you are experiencing G5 every part your body feels five times as heavy as it does on Earth.
Those drivers in the F1 motor races also experience greater G force when they turn around bends. You can see their heads moving from side to side, and it's very tiring.
Potential energy is the energy stored in a body or in a system due to its position in a force field or due to its configuration.
Orbit is the gravitationally curved path of one object around a point or another body, for example the gravitational orbit of a planet around a star.
A "point" is an abstract concept, it's infinitely small and has no mass. A real object would have mass and create a gravitational field on it's own, regardless of whether or not it was inside a hollow sphere. We have to observe circular motion and Linear velocity. Potential energy is energy that is stored within a system. It exists when there is a force that tends to pull an object back towards some lower energy position.
According to the law of conservation of energy, energy cannot be created or destroyed; hence this energy cannot disappear. Now we have...
Gravitational energy whcih is the potential energy associated with gravitational force.
Hence the moon is smaller than the Earth, combining these reasonings, the moon will never have a gravitional potencial equal to the Earth.
How do I solve this calculus problem regarding drag force and gravity?
I'm having trouble finding the relation between velocity and time given this formula. If anyone has a solve for this, It would be great if you took your time to help me as I know this includes differential acceleration, which requires calculus. As velocity increases, drag force increases - until terminal velocity.
F=1/2 * p * v^2 * C * A
p is density of fluid and is set to 1.225 kg/m^3
v is velocity of object relative to fluid
C is Coefficient of Drag and is set to 0.9, as my shape is a sphere
A is cross-sectional area which is π/4, as it is the "CS" of a sphere where diameter of "CS" circle in sphere is 1.
From my knowledge, I was only able to proceed this far:
Lets assume 1/2 * p * v^2 * C * A=ma1
Lets assume k=1/2pC (A is not included because I'll be comparing graphs with different values for A)
F=ma is the Net Force
g=9.80665m/s/s
F=mg
mg-ma1=ma
Force of gravity-Force of Drag=Net Force.
mg - 1/2 * k * v^2 * A = ma
g - (1/2 * k * v^2 * A) / m = a
How do I proceed? Do I differentiate a for dv/dt and integrate it later? I suck at calculus and I don't understand much of its logic, please help. If you have extra time, please give me a graph for velocity given time and acceleration given time.
Does earth's gravity do any work on satellite revolving around it?
NO.
The gravity of Earth, in conjunction with the inertia of the satellite, keeps the satellite revolving around Earth.
However, the satellite doesn't get any nearer to the Earth. So, according to the laws of physics, no work is done.
(I'm ignoring the fact that satellites sometimes lose height and need to be "boosted" a bit to maintain their orbits.
Also, I'm assuming that the satellite's orbit is circular. If the orbit is elliptical the answer is more or less the same, but a bit more complicated.)
To determine the value of g acceleration due to gravity by means of a compound pendulum?
you can also use a simple pendulum to do it. your brain is full of problems if you cant do it by the easier way
Forget that
go on to this site and it gives you a method/procedure also go through www.phy.iitkgp.ernet.in/1styr/11-compound-pendulum.pdf
By definition, a centripetal force is a force towards a central point, exerted on an
object following a curved path. It causes an object to follow a curved path, such
as an orbit; this is what the gravitational force of the sun does to planets. So it
is clearly a centripetal force.
A centrifugal force is defined as a force that is exerted away from a center
around which an object either rotates or revolves. Literally, in terms of etymology,
centrifugal means fleeing the center. Planets orbit the sun because of a balance
of centripetal and centrifugal forces. If there were only an attractive force pulling
a planet toward the sun, the planet would fall into the sun. And if there were only
a centrifugal force pulling planets away from the sun, the planets would fly out of
the solar system and into interstellar space. But since these two forces are balanced,
planets remain in orbit around the sun.
An object on which the forces are balanced travels in a straight line at constant
speed. The planets do not travel in straight lines or at constant speeds, because
the forces on them are not balanced. The only force on a planet is the centripetal
force of gravitational attraction between it and the sun. That single force produces
all of the orbits we observe, whether elliptical (repeating) or hyperbolic (not repeating).
Those orbits are fairly easy to derive using Newton's formula for gravitational force
and direction, plus some geometry and some calculus.
Non-furious comments: I avoid writing "centrifugal force", by writing "centrifugal effect".
I think that's more or less OK, depending on your "audience".
Technically "centrifugal force" is called a "fictitious force".
It is actually correct to use it in a rotating frame of reference.
Unfortunately, it is often used incorrectly, even by educators.
Luckily, the answer to the question was "centripetal force".
<<>> The physical processes are that there is a force of gravity pulling the Sun and Earth towards each other. The force acts equally both ways, producing an acceleration in both objects, towards each other, following Netwon's second law: force equals mass times acceleration. The Sun's much greater mass means that its acceleration is small, while the Earth's acceleration towards the Sun keeps it in its elliptical orbit. That is what's happening, so for those who can't remember the difference between centrifugal and centripetal, don't worry, they are not terms used by astronomers.
First, this isn't a simple "statics" problem. For example, the Moon is orbiting Earth. Also the Earth-Moon distance varies (elliptical orbit).
(The distances mentioned below are, strictly speaking, distances from the centres of the Earth and Moon.)
However, a simple answer is: at about a tenth of the Earth-Moon distance from the Moon. Here's why:
The Moon's mass is about 1/81 of the Earth's mass.
Gravitational force is directly proportional to the mass of an object.
Gravitational force is inversely proportion to the square of the distance between objects.
When the ratio of the distance to Moon to the distance to the Earth is 1/9
gives the "neutral gravity point". That's because 1/9 x 1/9 = 1/81.
So, the place where the Moon's gravity takes over is one tenth of the Earth-Moon distance from Moon.
The Moon's average distance from Earth is about 238,000 miles. That means the answer is: at about 23,800 miles from the Moon.
(Remember there are other ways of looking at this problem. There is more than one "correct" answer, depending on your approach.)
How do you gravity moon gravity in Tony Hawk's American Wasteland?
you enter "2them00n" (without the quotation marks and the 0 are zeros) under cheat codes
How can you move a standard vehicle with gravity?
You just have to put the car in neutral and the gravity will move it.
What does gravity prevent the earth from doing?
It prevents the earth from spinning off in a straight line away from the sun instead of falling back into the sun.
The attractive forces between sun and earth or among other planets is counter acted by the centrifugal force that tends to pull them apart.
Adding to the above answer:
Imagine swinging a ball around over your head on the end of a string. If you swing the ball fast enough it will stay out at the end of the string and remain in the air. The string keeps it from flying off and the centrifugal force caused by the twirling keeps it from falling. But, if the rotational speed of the ball slows down, at some point it will fall. The string is like the gravitational force holding the planet to the Sun keeping it from flying off into space, and the rotation of the planet in it's orbit around the Sun causes a centrifugal force which is counteracting the Sun's gravitational attraction. If the speed at which the planet is going around the Sun slows below a certain amount the gravitational force will win and the planet will fall into the Sun. When the solar system first formed there were all kinds of bodies whirling around the Sun, but those at the wrong speed either fell into the Sun or flew off into space. So, today all that are left are the ones circling at just the right speed.
Is it gravity constant G times mass?
If you mean the force of gravity, the force of gravity on Earth is equal to the mass of an object, times Earth's gravitational field (which is about 9.8 newton/kilogram).The gravitational force between ANY two masses, on the other hand, is given by:
force = G m1 m2 / r squared
Where m1 and m2 are the two masses involved, "r" is the distance between them, and "G" is the universal gravitational constant.
Does mass measurement include the effect of earth's gravitational pull on the object being measured?
Mass is not affected by gravity. When you measure the mass of an object with a balance, you would get the same result under any gravitational conditions except for under micro- or zero gravity, in which case there would be insufficient force to move the balance to equilibrium. If you use a spring balance, you are not getting a true mass measurement, you are getting a weight measurement that is normalized to provide the mass at that particular gravitation.
In a micro- or zero gravity field, you can obtain the mass by measuring the vibration or oscillation of the object (pendulum action).
Would gravity exist even if the earth stopped rotating?
Yes, indeed it would. Gravity is not caused by the rotation of the Earth. In fact, there would be a very small increase in the "apparent gravity" at the Earth's surface because of the lack of a "centrifugal" effect.
A T-mobile phone that is supposed to be better than a gravity phone.
What is Venus's gravitational pull in meters per second squared?
The acceleration of gravity on or near the surface of Venus is 8.87 m/s2 . . .
about 91% of its value on or near the surface of Earth.
What velocity if a body strike the ground which was dropped from the height of 176.4m?
The formula for a socalled "free fall" velocity (v in m/s) is:
v = SQRT [2.g.h]
in which g = 9,81 m/s2 (mean gravitational accelleration on earth) and h is the falling highth in metres.
Calculating: v = SQRT[2 * 9.81 * 176.4] = SQRT[3461] = 58.8 m/s
So, ONLY if no resistance (eg. from air) is conteracting the force by gravity, then the velocity at ground level will be 58.8 meter per second and by then this is also independent from the falling mass (theoretically).
However, depending on measures, mass and surface area and roughness, the air resistance can play a major role in decreased veleocity: look at hail, rain drops, and fogg: same density, different surface, and fogg will never reach ground (!), but I would like to miss being bombed by large hail stones from 150 m high!
Does Pluto have a stronger gravitational pull as compared to Jupiter?
No. Jupiter's gravity is much stronger than Pluto's
The strength of gravity from a given object is directly proportional to the object's mass and inversely proportional to the square of the distance from the center of mass. So, if we double an object's mass the gravity is double. If we triple the mass the gravity is tripled. By contrast if we double the distance we end up with one quarter the gravity. If we triple the distance we end up with only one ninth the gravity.
The formula for the strength of gravity is: g=G*M/r^2
"G" is the Newtonian gravitational constant, "M" is the mass of the object, and "r" is the distance tot he center of mass.
In the case of the surface gravity of a planet, the distance to the center of mass is the planet's radius. So if two planets have the same mass but are of different sizes, the larger planet will actually have weaker surface gravity. In most cases a larger planet will have a greater mass than a smaller one, but not always as planets vary in density. Event if the larger planet is more massive, the larger size can still result in weaker gravity.
A perfect example would be a comparison between Earth and Uranus. Uranus is about 4 times the radius and about 14.5 times the mass of Earth. From these figures we find that the gravity on Uranus is 0.906 times or 90.6% of Earth's surface gravity.
