QBasic

cls
input" enter any string";a$
f=Len(A$)
d=1
AA:
b$= mid$(a$,d,1)
d=d+1
c=asc(b$)
if c=101 or c=105 or c=970 or c=111 or c=117 then
cnt= cnt+1
end if
if d<=f then goto aa
print cnt;
end

ALGORITHM EVEN

BEGIN

FOR ( num = 0; num <= 20; num++ )

BEGIN

IF ( num MOD 2 == 0 ) THEN

DISPLAY (num)

END IF

END FOR

END EVEN

in C:

#include <stdio.h>

int main (void) { puts ("0 2 4 6 8 10 12 14 16 18 20"); return 0; }

A linear queue models the FIFO(first in first out) data structure, much like a line in real life. The first person in line will be the first person served, in queues the first element to be added is the first that can be removed. The only adding point is to the end of the list and the only removal point is the beginning of the list.

Queue<String> q = new LinkedList<String>(); // The LinkedList class implements Queue

q.add("Bob"); // Now Bob is at the front of the queue

q.add("Stacy"); // Stacy after Bob

q.add("Will"); // and Will after her

String removed = q.remove(); // Bob is removed

q.add("Michael"); Michael is added after Will

System.out.println(q); // Prints ["Stacy", "Will", "Michael"]

The control structures used in java script are if-statement, for-loop, for-in loop, while loop,do-while loop, switch-statement, with-statement. try-catch-finally statements.

I'm not too sure that I understand exactly what you mean by 'add a square'...?! Thus, I will attempt to answer the question using multiple different ways; hoping that, least, 'one' of these answers might be right...

==>

CLS

PRINT "PROGRAM: Twelve Times Tables Number Square"

PRINT

FOR intTimes% = 1 TO 12

FOR intTables% = 1 TO 12

sum% = intTimes% * intTables%

noOfSpaces% = 0

IF LEN(STR$(sum%)) = 2 THEN noOfSpaces% = 2

IF LEN(STR$(sum%)) = 3 THEN noOfSpaces% = 1

PRINT sum%; SPC(noOfSpaces%);

NEXT

PRINT

NEXT

END

<==

...QBASIC Code/End.

Create a form with two text boxes (txtNumber1, and txtNumber2) and a command button (cmdSwap).

Option Explicit

Dim numb1 As Variant

Dim numb2 As Variant

Private Sub cmdSwap_Click()

numb1 = txtNumber1.Text

numb2 = txtNumber2.Text

txtNumber2.Text = numb1

txtNumber1.Text = numb2

End Sub

cls

a =1

for i = 1 to 5

print a;

a = (a*10)+1

next i

end

Some languages have specific terms, however keyword or reserved word is the general terminology we use when referring to a programming language's primary vocabulary. That is; words that cannot be used as identifiers. However, some languages also have contextual keywords. For instance, C++ has final and override contextual keywords. These can be used as both identifiers and keywords, depending on the context. The only reason for this is that people were using these words as identifiers before they were introduced to the language (in C++11) and making them actual keywords would have broken a lot of older code.

QBASIC CODE/START...

====

...QBASIC CODE/END.

8

@...the AT symbol is located...on my 'own' keyboard, at least, next to the [COLON(:)/SEMI-COLON(;)] key. It's above the [single quote(')/(@)]...that means it's an UPPER CASE symbol.

To obtain UPPER CASE 'letters/symbols/numbers' that are shown on your keyboard...you need to...

1. press, and, hold down the [SHIFT] button key...

-(which is, usually, shown as being an 'upwards arrow'...there are two [SHIFT] button keys, each located on either side of the keyboard, next to/and, on top of both the [CTRL] keys)-

2. ...whilst at the same time, pressing down the [@] symbol key.

====

SOME FURTHER NOTES

ASCII/American Standard Code for Information Interchange, uses the numbers:

-> 65-90, to represent UPPER CASE alphabet letters: A-Z

-> 97-122, to represent 'lower case' alphabet letters: a-z

-etc.

You can have a go at experimenting, try typing in all of the ASCII code numbers: 0-255;

to discover seeing what character comes up, next...?!

NOTE: Some ASCII number codes are, in fact, 'invisible' characters that will NOT display...;

such as ASCII number 32 represents a [SPACEBAR] key invisible 'space' character/

too, there is the invisible [TAB] character key which also won't display/-etc.

'*** PROGRAM: Compare 2 numbers using both min/max functions;

' then, output which number is max/and, which is min.

'*** declare variables...

min = 0

max = 0

number1 = 342

number2 = 256

'*** main program...

CLS '...(CL)ear the Output (S)creen

PRINT "Minimum = "; findMin(number1, number2)

PRINT "Maximum = "; findMax(number1, number2)

END '...END of program/halt program code execution

FUNCTION findMax (num1, num2)

answer = 0

IF num1 > num2 THEN answer = num1 ELSE answer = num2

findMax = answer

END FUNCTION

FUNCTION findMin (num1, num2)

answer = 0

IF num1 < num2 THEN answer = num1 ELSE answer = num2

findMin = answer

END FUNCTION

---program output...

Minimum: 256

Maximum: 342

Store the numbers in a suitable container such as an array. Assume the first number is the smallest and assign its value to a local variable. Traverse the remainder of the sequence, comparing each element's value to the stored value. If an element has a lower value, assign its value to the local variable. When the sequence is fully traversed, the local variable will hold the value of the smallest value in the sequence. Return that value.

#include<stdio.h>

#include<conio.h>

main()

{

int a[4][4],b[4][4],c[4][4],i,j;

printf("enter the elements of matrix a");

for(i=0;i<=3;i++)

for(j=0;j<=3;j++)

scanf("%d",&a[i][j]);

printf("the first matris is");

for(i=0;i<=3;i++)

{

printf("\n");

for(j=0;j<=3;j++)

printf("%d",a[i][j]);

}

printf("Enter the elements of second matrix");

for(i=0;i<=3;i++)

for(j=0;j<=3;j++)

scanf("%d",&b[i][j]);

printf("the second matrix is");

for(i=0;i<=3;i++)

{

printf("\n");

for(j=0;j<=3;j++)

printf("%d",b[i][j]);

}

for(i=0;i<=4;i++)

for(j=0;j<=4;j++)

c[i][j]=a[i][j] + b[i][j];

printf("the addition of matrix is");

for(i=0;i<=3;i++)

{

for(j=0;j<=3;j++)

printf("%d\t",c[i][j]);

printf("\n");

}

getch();

}

CLS

a = 0

b = 0

FOR i = 1 TO 10

IF a = 0 THEN

f = 1

END IF

PRINT f

b = a

a = f

f = a + b

NEXT i

END

from : Parth jani

parthjani7@yahoo.com

cls

total=0

for i=0 to 20 step -2

total = total+i

print i ;

next i

print "total is " total

end

send by tripti

You can't. If you want to pause between each command you have to step through the commands one at a time, or set a breakpoint at the point you wish to start stepping through.

No, Process is an active entity. Program, on the other hand, is a passive entity.

Drawing natural looking trees in any programming language is difficult. The problem is trees (and many other living things) grow in a fractal manner, so look up "fractal mathematics" for ideas. If you don't want to do this research, then you can draw one on paper as you think it should look and hand code the program to exactly duplicate your paper drawing (but when I tried this in the early 1980s it came out looking worse than "a Charlie Brown Christmas Tree").

As to presents and decorations, they are quite trivial as they are almost always regular geometric shapes.

Just remember to have at least some of the lights flashing on and off and have Santa Claus in his Sleigh with all his Reindeer do a flyby in the background! These are all simple animations and much easier than coding a natural looking tree.

In my case back in the early 1980s I approximated a simple "step, scale, and repeat" type fractal to create the branches using some special graphics operations in the special purpose graphics programming language that I was using that qBasic does not have (although you could implement something like them with several subroutines that your main program would call). Although it still wasn't perfect it did produce a feel of a natural looking tree without requiring any really complicated code. I won the "Most Original Tree" prize at work that year and the next year was asked to rewrite it slightly (without animations) so it could be photographed for the Company Christmas Card!

REM any text

The following code will produce a list of numbers in steps of 2. It can be modified for any start & end number, and the size of the step.

start% = 21

end% = 29

FOR num% = start% TO end% STEP 2

PRINT num%

NEXT

The above code will produce the results 21,23,25,27 & 29