C Programming

Each number separated by a dot is an eight bit number, so conversion requires converting four numbers. To convert a decimal number to binary, divide by two in succession until the number zero is reached.

121 / 2 = 60 r 1

60 / 2 = 30 r 0

30 / 2 = 15 r 0

15 / 2 = 7 r 1

7 / 2 = 3 r 1

3 / 2 = 1 r 1

1 / 2 = 0 r 1

Then, you read remainders backwards:

1111001

If there's less than 8 numbers, add zeroes to the left:

01111001

Then, do this for the other numbers.

55 / 2 = 22 r 1

22 / 2 = 11 r 0

11 / 2 = 5 r 1

5 / 2 = 2 r 1

2 / 2 = 1 r 0

1 / 2 = 0 r 1

00101101

7 / 2 = 3 r 1

3 / 2 = 1 r 1

1 / 2 = 0 r 1

00000111

15 / 2 = 7 r 1

7 / 2 = 3 r 1

3 / 2 = 1 r 1

1 / 2 = 1 r 1

00001111

Once you have all the binary digits, simply stick them back together using dots:

01111001.00101101.00000111.00001111

It can be. It can also not be.

Use charmap.exe, (you can use these characters: ĆĈĊČ, and many others)

Int: 4 bytes

Float: 4

double: 8

char: 1

boolean: 1

What is asking about something -- what is your name

When is asking about time date -- when were you born

I have left the question marks(?) off the questions because Wiki answers doesn't like answers with questions

One can use language that expresses uncertainty or possibility, such as using words like "may," "might," "could," or "potential." By using these types of words, it allows for flexibility and avoids making a definitive statement. Additionally, using conditional language like "if," "unless," or "depending on" can also help to avoid making a definite statement.

You can, but it's not as straightforward as inserting or deleting from a list. This is simply because arrays are not intended for insertions or deletions other than at the end of the array. This is because an insertion requires that the entire array be reallocated (which may require the array to be copied in its entirety) simply in order to make room for the new element, which can then simply be inserted in the unused element at the end of the new array. To insert elsewhere in the array, all the elements following the insertion point need to be copied (for a second time) into the next element, starting with the last used element. the entire process can prove quite costly, especially if the elements are complex objects which would require their copy constructors to be invoked at least once and possibly twice. This is why it is generally better to use arrays of pointers to objects rather than arrays of objects, as copying a pointer is more efficient than copying an object. However, if your array undergoes frequent resizing in order to accommodate insertions and deletions, then you really would be better off using a list.

#include<stdio.h>

#include<conio.h>

#include<graphics.h>

#include<stdlib.h>

#define pf printf

#define s scanf

int gd=DETECT, gm, pa, o, b;

int i;

int x, y, i,ch,c;

int c, m, p, qn, cm, mp, cp, cmp, n, k, p1, g,qcm,qmp,qcp,qc,qm,qp;

void main()

{

initgraph(&gd,&gm," ");

cleardevice();

line(0,0,639,0);

line(0,0,0,479);

line(639,0,639,479);

line(639,479,0,479);

line(589,479,0,479);

randomize();

for(i=0;i<640;i++)

{

setcolor(i);

x=rand()%639;

y=rand()%480;

putpixel

(x,y,i);

{

setcolor(RED);

settextstyle(3,0,5);

outtextxy(60,100, "PROJECT IN DISCRETE");

setcolor(RED);

settextstyle(3,0,5);

outtextxy(80,135, "MATHEMATICS");

setcolor(i);

settextstyle(2,0,5);

outtextxy(120,192,"SUBMITTED BY :");

setcolor(i);

settextstyle(2,0,5);

outtextxy(120,202,"Cabrera");

setcolor(i);

settextstyle(2,0,5);

outtextxy(120,214,"Gaspar");

setcolor(i);

settextstyle(2,0,5);

outtextxy(120,226,"Molina");

setcolor(i);

settextstyle(2,0,5);

outtextxy(120,238,"Viray");

}

setcolor(i);

settextstyle(2,0,5);

outtextxy(400,350,"U P L O A D i N G...");

setcolor(WHITE);

outtextxy(i,378,"=");

outtextxy(i,406,"=");

setcolor(WHITE);

circle(i,400,10);

delay(1);

}

cleardevice();

gotoxy(10,7);

pf("Enter 1 for V E N N D I A G R A M ");

gotoxy(10,8);

pf("Enter 2 for S E T N O T A T I O N");

gotoxy(10,10);

printf("Input: ");

s("%d",&pa);

cleardevice();

{

if(pa==1)

{ {

line(0,0,639,0);

line(0,0,0,479);

line(639,0,639,479);

line(639,479,0,479);

line(589,479,0,479);

randomize();

for(i=0;i<640;i++)

{

setcolor(i);

x=rand()%639;

y=rand()%480;

putpixel

(x,y,i);

{

setcolor(i);

settextstyle(9,0,5);

outtextxy(60,100, "V E N N");

setcolor(i);

settextstyle(9,0,5);

outtextxy(80,165, "D I A G R A M");

}

setcolor(i);

settextstyle(2,0,5);

outtextxy(400,350,"U P L O A D i N G...");

setcolor(YELLOW);

outtextxy(i,378,"=");

outtextxy(i,406,"=");

setcolor(WHITE);

circle(i,400,10);

delay(1);

}

sleep(1);

cleardevice();

}

gotoxy(10,7);

pf("Enter 1 if the Outside is missing. 3 Circle. ");

gotoxy(10,8);

pf("Enter 2 if the Total is missing. 3 Circle.");

gotoxy(10,11);

printf("Choice : ");

s("%d",&p1);

for(g=1;g<=8;g++)

{ if(p1==1)

{

cleardevice();

gotoxy(32,8);

pf("Input the Values for the following variables:");

gotoxy(32,11);

pf("X:");

gotoxy(32,12);

pf("Y:");

gotoxy(32,13);

pf("Z:");

gotoxy(32,14);

pf("XY:");

gotoxy(32,15);

pf("XZ:");

gotoxy(32,16);

pf("YZ:");

gotoxy(32,17);

pf("XYZ:");

gotoxy(32,18);

pf("Outside:");

gotoxy(32,19);

pf("Total Number:");

{

if(g==1){gotoxy(42,18);pf("----");gotoxy(42,11);s("%d",&c);}

if(g==2){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);s("%d",&m);}

if(g==3){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);s("%d",&p);}

if(g==4){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);scanf("%d",&cm);}

if(g==5){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);s("%d",&cp);}

if(g==6){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);s("%d",&mp);}

if(g==7){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);s("%d",&cmp);}

if(g==8){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);pf("%d",cmp);gotoxy(50,19);s("%d",&k);}

cleardevice();

}}

{ qcm=cm-cmp;

qmp=mp-cmp;

qcp=cp-cmp;

qc=c-(qcp+cmp+qcm);

qm=m-(qcm+cmp+qmp);

qp=p-(qcp+cmp+qmp);

qn=k-(cmp+qcp+qcm+qmp+qc+qm+qp);

}

cleardevice();

setcolor(RED);

rectangle(600,450,40,40);

setcolor(YELLOW);

circle(250,200,125);

setcolor(GREEN);

circle(375,200,125);

setcolor(BLUE);

circle(313,300,125);

gotoxy(39,15);

printf("%d",cmp);

gotoxy(30,4);

printf("X");

gotoxy(49,4);

printf("Y");

gotoxy(23,12);

printf("%d",qc);

gotoxy(55,12);

printf("%d",qm);

gotoxy(39,23);

printf("%d",qp);

gotoxy(39,9);

printf("%d",qcm);

gotoxy(30,18);

printf("%d",qcp);

gotoxy(49,18);

printf("%d",qmp);

gotoxy(63,25);

printf("%d",qn);

gotoxy(39,27);

setcolor(WHITE);

outtextxy(310,435,"Z");

}

for(g=1;g<=8;g++)

{

if(p1==2)

{cleardevice();

gotoxy(32,8);

pf("Input the Values for the following variables:");

gotoxy(32,11);

pf("X:");

gotoxy(32,12);

pf("Y:");

gotoxy(32,13);

pf("Z:");

gotoxy(32,14);

pf("XY:");

gotoxy(32,15);

pf("XZ:");

gotoxy(32,16);

pf("YZ:");

gotoxy(32,17);

pf("XYZ:");

gotoxy(32,18);

pf("Outside:");

gotoxy(32,19);

pf("Total Number:");

{

if(g==1){gotoxy(42,19);pf("----");gotoxy(42,11);s("%d",&c);}

if(g==2){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);s("%d",&m);}

if(g==3){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);s("%d",&p);}

if(g==4){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);scanf("%d",&cm);}

if(g==5){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);s("%d",&cp);}

if(g==6){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);s("%d",&mp);}

if(g==7){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);pf("%d",cmp);gotoxy(42,18);s("%d",&n);}

cleardevice();

}}

{ qcm=cm-cmp;

qmp=mp-cmp;

qcp=cp-cmp;

qc=c-(qcp+cmp+qcm);

qm=m-(qcm+cmp+qmp);

qp=p-(qcp+cmp+qmp);

qn=k-(cmp+qcp+qcm+qmp+qc+qm+qp);

}

cleardevice();

setcolor(RED);

rectangle(600,450,40,40);

setcolor(YELLOW);

circle(250,200,125);

setcolor(GREEN);

circle(375,200,125);

setcolor(BLUE);

circle(313,300,125);

gotoxy(39,15);

printf("%d",cmp);

gotoxy(30,4);

printf("X");

gotoxy(49,4);

printf("Y");

gotoxy(23,12);

printf("%d",qc);

gotoxy(55,12);

printf("%d",qm);

gotoxy(39,23);

printf("%d",qp);

gotoxy(39,9);

printf("%d",qcm);

gotoxy(30,18);

printf("%d",qcp);

gotoxy(49,18);

printf("%d",qmp);

gotoxy(63,25);

printf("%d",qn);

gotoxy(39,27);

setcolor(WHITE);

outtextxy(310,435,"Z");

}

}

getche();

}

{

if(pa==2)

{

{

line(0,0,639,0);

line(0,0,0,479);

line(639,0,639,479);

line(639,479,0,479);

line(589,479,0,479);

randomize();

for(i=0;i<640;i++)

{

setcolor(i);

x=rand()%639;

y=rand()%480;

putpixel

(x,y,i);

{

setcolor(i);

settextstyle(9,0,5);

outtextxy(60,100, "S E T");

setcolor(i);

settextstyle(9,0,5);

outtextxy(50,165, "N O T A T I O N");

}

setcolor(i);

settextstyle(2,0,5);

outtextxy(400,350,"U P L O A D i N G...");

setcolor(YELLOW);

outtextxy(i,378,"=");

outtextxy(i,406,"=");

setcolor(WHITE);

circle(i,400,10);

delay(1);

}

sleep(1);

cleardevice();

}

printf("ogi");

getche();

}

}

cleardevice();

gotoxy(10,10);

printf("--END--");

getche();

}

They don't.

A loop tool is used to smooth and model clay into shape. The tool has a wooden handle and a metal loop at the end that can come in different sizes.

A binary operator is simply an operator that has two parts, written to the left and to the right of the operator, e.g.:

1 + 2

The binary operator can be a logical operator ("and", "or", "xor", etc. - but "not" is a unary operator), or it can be in some other category, like the arithmetic operator shown above.

A binary operator is simply an operator that has two parts, written to the left and to the right of the operator, e.g.:

1 + 2

The binary operator can be a logical operator ("and", "or", "xor", etc. - but "not" is a unary operator), or it can be in some other category, like the arithmetic operator shown above.

A binary operator is simply an operator that has two parts, written to the left and to the right of the operator, e.g.:

1 + 2

The binary operator can be a logical operator ("and", "or", "xor", etc. - but "not" is a unary operator), or it can be in some other category, like the arithmetic operator shown above.

A binary operator is simply an operator that has two parts, written to the left and to the right of the operator, e.g.:

1 + 2

The binary operator can be a logical operator ("and", "or", "xor", etc. - but "not" is a unary operator), or it can be in some other category, like the arithmetic operator shown above.

Masking

create a program that can input 100 names

fish

The time.h include file is a header file for a library of standard time and date manipulation routines. For example...

#include <stdio.h>

#include <time.h>

int main (int argc, char ** argv) {

time_t tt = time(NULL);

printf ("The date and time is %s", asctime(localtime(&tt)));

return 0;

}

Just fart!

yes

AND and NOT; OR and NOT; EQU and NOT; XOR

Hashing provides a method to search for data.

Hashing provides a method to search for data.

Hashing provides a method to search for data.

Hashing provides a method to search for data.

A repeater contains one input port and one output port, so it is capable only of receiving and repeating a data stream.

#include<stdio.h>

int main(){

int a[3][3],b[3][3],c[3][3],i,j;

printf("Enter the First matrix->");

for(i=0;i<3;i++)

for(j=0;j<3;j++)

scanf("%d",&a[i][j]);

printf("\nEnter the Second matrix->");

for(i=0;i<3;i++)

for(j=0;j<3;j++)

scanf("%d",&b[i][j]);

printf("\nThe First matrix is\n");

for(i=0;i<3;i++){

printf("\n");

for(j=0;j<3;j++)

printf("%d\t",a[i][j]);

}

printf("\nThe Second matrix is\n");

for(i=0;i<3;i++){

printf("\n");

for(j=0;j<3;j++)

printf("%d\t",b[i][j]);

}

for(i=0;i<3;i++)

for(j=0;j<3;j++)

c[i][j]=a[i][j]+b[i][j];

printf("\nThe Addition of two matrix is\n");

for(i=0;i<3;i++){

printf("\n");

for(j=0;j<3;j++)

printf("%d\t",c[i][j]);

}

return 0;

}

Please refine your question, it is not precise enough to get a clear understanding of what you are asking.

i dont know please give some idea to develope in sensor coding

The break statement exits out of the smallest containing loop or switch-case statement. The continue statement transfers control to the next iteration of the smallest containing loop statement.