Electronics Engineering

The time base of an oscilloscope is used to increase or decrease the time per division value on the Y-axis ranging from few tens of seconds to micro seconds to nanoseconds used for microwave signals.If you increase the time base of an oscilloscope lesser and lesser part of the signal will be present in one division of the Y-axis. Setting the time base to a proper value will enable you to see high frequency signals clearly otherwise each cycle of the signal would be indistinguishable from the other huehue

To calculate the current through an LED, use the following formula

Current = (Source_voltage - Led_voltage_drop)/Resistance

Now if you didn't use a resistor, the you only have the resistance in the wire, which is very small (eg .001 ohm).

So if you have for instance a 9V battery, and a 2.1 volt drop across the LED, the resultant current would be so high, it would destroy the LED.

We put a resistor in to lower the current to an acceptable range (often 20-30ma)

Unless it's an old vw bug, cars usually run on a 12 volt dc system nowadays.

Motorcycles often run on a 6 volt dc system.

Different systems require different charging voltages so you won't ever be able to charge a 12 volt car battery from a 6 volt motorcycle battery charger as the output voltage would be way too low.

However, if you can set the battery charger's output to give either a 6 or a 12 volt output, then you must always remember to set it to 12 volts if you want to use it to charge a 12 volt car battery.

Yes, you can. Here's why.

If a supply's output is rated at 12 volts DC (12 VDC) and 500 milliamperes (500mA), it can deliver a maximum of 500mA at the 12 volt rating. You want to use a 12VDC supply that is rated at 1A (1000mA). That means that the supply is capable of delivering up to 1A at 12VDC. Now the crux of the matter.

Your device, that's the load on the supply, needs 12VDC to operate. Your replacement supply is rated at 12VDC. No problem. Your supply delivered a max of 500mA. That does NOT mean that your load, that thing you're powering up, actually uses all 500mA. Your load knows how much current it needs to draw. Your supply has to be rated for more than that. Your supply was rated at 500mA. It worked well. The supply you wish to use will deliver a max of 1A (1000mA). It will easily supply the current your load will use. Oh, and the polarity of the new supply must be the same as that of the old one. That's pretty obvious. Always be safe and consult an electronics specialist for electrical questions. There are a number of savvy folks working at consumer electrical outlets who can get you up to speed.

Gray code is useful because only one bit changes at a time. When used as encoders for a position sensor, for instance, if the sensor were right at the edge of a change boundary, there is uncertainty as to position. Binary code would introduce variable uncertainty in position, because more than one bit can change at a time, but gray code would reduce that uncertainty to being only one bit position in size.

Resistance, and therefore resistors, are a part of any electrical conductor. They were not created but rather, discovered and put to use in electrical and electronic circuits.

DWDM (Dense Wavelength Division Multiplexing)

If you really work hard every course has a good scope.

As we bring P type and N type semiconductors fused together, then rich holes in P type would get neutralized with some rich electrons in N type. Hence at the juntion region, there will not be charge carriers ie holes and electrons. So it is known as Depletion Region. Depletion means emptying something. In case of ordinary diode this depletion region would be wider where as in case of Zener Diode the depletion region would be narrower. This is because the semiconductors are heavily doped. Hence potential barrier would be easily built up even with a thin region where holes and electrons get combined for neutrelization.

I assume a series of amplifiers with one F/B The F/B is the portion of voltage/current F/B from input to output no matter how many amplifiers are in series within the loop or what the gain of each one is.

A battery is usually thought of as a source, not a load. If you are charging a battery, then it will be resistive, especially if you are attempting to charge it like you should, with a DC power supply (not AC).

A digital multimeter is a instrument which is used to measure voltage, current, resistance also it can measures frequency and periodic waveforms. It manly used as test equipement, for example if you had created a circuit you can use it to see if there a fault so then it can be corrected.

Digital meters tend to be more accurate, as they have a very high input impedance, so have less affect on the circuit being measured.

Having a digital output gets round the parallax problem reading a needle.

Having no moving parts, makes them more rugged and less likely to get out of calibration.

The only downside of a digital meter is its harder to see a fluctuating measurement. Watching a needle is better in this case, than watch numbers change.

........V

I = ------

........R

I = Ohm's Law

V = Voltage

R = Resistance

(Ignore the dots they stop V and R from moving to the left!)

Yes you can. All the 1300 mA rating means is that adaptor can supply devices up to 1300 mA. The old adaptor's limit was 800 mA. The new adapter has 500 mA more in reserve if it is ever needed.

Yes, you can wire a 6 ohm sub with a 4 ohm sub to the same amplifier, but you need to verify that the amplifier can handle the resulting impedance of 2.4 ohms - many cannot, and could be destroyed. Also, realize that the power in the 4 ohm sub will be greater than the power in the 6 ohm sub.

Biasing the transistor so that it remains into the linear range is one way the other way is to couple one stage to another via a capacitor to remove extra biasing DC voltage therefore remaining into the linear range

rms value of ac power = dc power in reference to heat production in pure resistive load

So ac power of some rms value will produce the same heat in resistive load as dc power will of same value

Two words: skin effect. Now let's chat. Picture a wire with DC flowing through it. We are going to look at a cross section of the wire without interrupting current flow. Make sense? Picture it. When current flows in a wire in only one direction (DC), it uses all the available metal in the wire. Current flow in the middle of the wire will be about the same per unit of cross sectional area as current flow will be near the outside of the wire. Let's switch our DC for some AC. AC (alternating current) will flow in one direction for a while and then reverse direction to flow the other way for a while. Such is AC. And AC will cause current flow that uses all the available cross sectional area of the wire just as DC does, but only at low frequency. At higher and higher frequencies, current flow in the wire will shift away from the center and be more concentrated near the surface of the conductor. Near the skin of the conductor. AC of higher frequencies will promote current flow by skin effect, and that is the effect of frequency in AC current flow.

No, a miliohm is 0.001 ohms. A kiloohm is 1000 ohms.

A: desirable oscillator will have no frequency deviation as a function of external influences such as temperature and more. Stability is measured as a % factor considering outside interferences

As we know thath insulators are the materials which are mainly use to insulate any conducting body from the LIVE supply whether 3Ph or single phase, so the reristence of such an insulator should be infinity as it should be provide maximum resistance to the flow of current through it.

You should always where a ground strip when working on the internals of a computer. You should always unplug the computer from everything before working on it and ground yourself to the computers metal case. This will equalize the static electricity between you and the mother board and her components.

You cannot build a power tube amplifier without bias. At minimum, you need some kind of negative bias on the control grid, and you might need positive bias on the screen grid as well as cathode voltage on the suppressor grid.