Electronics Engineering

This question would be easier to answer if the type of IC was specified.

But generally, there are 3 reasons an IC will not work:

1. It is broken. If a large voltage or shock has been applied to it, or the power hooked up to it in reverse, an IC will usually burn out. This may or may not be accompanied with the release of the Magic Blue Smoke. (http://en.wikipedia.org/wiki/Magic_smoke)
2. Your power supply is dead or not outputting enough voltage. If the voltage supplied is too low for the IC to use, it may not function properly or at all. Check the power supply.
3. The circuit the IC is in is broken. Check all the wires/solder points. Test the IC in a known working circuit.

An analog signal is one which is continuous in time as well as continuous in amplitude . Example : sine wave, cosine wave. An Digital signal is one which is continuous in discrete in time. Example : square waves.

Plasma is a state of matter in the same way that solids, liquids and gases are also states of matter. Plasma is found in fluorescent light bulbs and is used to generate images in a plasma television. So, a television has the same kind of plasma as a light bulb but applied in different ways.

True.

You can test a capacitor using a multimeter and two leads by placing the multimeter in ohms mode. It works best with a needle type meter, not a digital meter.

Connect the leads to the capacitor and you will notice that the resistance pulses down, and then settles out at infinity. Reverse the leads, and you will notice the same effect, except that the pulse will be larger because the capacitor got charged in the opposite direction. Go back and forth.

This won't be apparent for very small capacitors because the pulse is too short.

Also, for electrolytic capacitors, they should only be charged in one direction, so you should start by discharging the capacitor and then connecting it in only one direction. Do not reverse the leads in this case. Just discharge and try again to see the effect.

Try this for various capacitors. You will notice that the pulse duration is larger for larger capacitance.

If the area of one plate of a parallel plate capacitor is increased while keeping the separation between the plates constant, the capacitance of the capacitor will increase. Capacitance is directly proportional to the area of the plates, as described by the formula ( C = \frac{\varepsilon A}{d} ), where ( C ) is capacitance, ( \varepsilon ) is the permittivity of the dielectric material between the plates, ( A ) is the area of the plates, and ( d ) is the separation distance. Thus, a larger plate area allows for greater charge storage, resulting in higher capacitance.

Vee clock is a kind of equipment used to hold circular workpieces. By clamping the the workpiece on it we can finder centre of the workpiece very easily as jt has a right angle slot in it. It can be also used for check the roundness of a circular job using a dial indicator.

You can glue toothpicks in layers around the egg then make a container for the egg to go in.Also, you can put super glue around the egg.I think if you did this your egg would withstand the fall.

eBooks are still "published" by publishing companies; while electronic references are just things like online encyclopedias.

For physical size-yes, if voltage rating is the same or more.

For capacitance size-it depends on where the cap is used. In an audio circuit, it may affect frequency response or distortion.

As with any solid state device the ratings vary greatly depending on the manufacture. For exact statistic consult the component manufacturer.

For FET:

A gate length of 1µm limits the upper frequency to about 5 GHz, 0.2µm to about 30 GHz.

For BJT:

??? could not find a general limit

A voltmeter can be connected in parallel with a resistor to show the voltage across the resistor.

If the total amount of energy (work done) is to remain the same, an increase in voltage yields a decrease in current.

P=I X E, where:

P is the power used by the load (the amount of work done) measured in watts

I is the current measured in amps

E is the EMF or voltage measured in volts

So, if we have a 1000W motor, we need to feed it with 8.3 A within a 120V circuit:

(1000W) = (8.3A) X (120V)

If we install the motor within a 240V circuit (assuming the motor is capable) the current is halved:

(1000W) = (4.17A) X (240V)

Bear in mind this doesn't allow for any of the inevitable losses that occur anytime we use or transmit power.

The disadvantage of automatic gain control, attenuating even the weak signal, is overcome by the use of delayed automatic gain control (dagc).

Check the internet to see if your charger will automatically step down to 7.2V (not likely if the charger is not the same brand as the battery). If it does not step down then it is possible but *** not recommended ***. Overvolting can cause nasty caustic leaking of toxic chemicals from the battery.

There is no way to store AC voltages as such. A battery is a storage device so AC is converted to DC for storage. When AC fails the stored DC voltage is then changed back to AC through a device called an inverter. The inverter outputs a square waveform instead of a sinusoid waveform but most loads, such as a computer power supply that is connected to the UPS, can not tell the difference.

It has a very sharp reverse breakdown voltage curve and is not damaged by the reverse current, as some normal diodes might be.

A small signal NPN transistor used for general purpose audio amplifiers and switching.

Try a pair of 2n1613 NPN transistors arranged as a darlington pair, collectors common, and Q1e tied to Q2b. input is on Q1b, output from + to the collectors. Ckt has hi input Z, and the slight conductive nature of rain water from + to Q1base will forward bias the switch.

Lo tech- a bargan basement smoke alarm- bridge the test contacts with a wet finger and it should go off. If that works, just solder wires and run them outside close together on a board to detect rain.

Like most other countries, you will find that in England we use voltages ranging from almost zero to a few tens of kV, depending on the application. ;)

However, assuming you mean the voltage supplied by 3-pin 13A mains sockets (type G) then from 1 January 2004 the mains supply should be 230V (-6%, +10%), 50 Hz (±1%). ie a range of 216.2 - 253V. This replaced the UK's former specification which was 240V ±6% (ie a range of 225.6 - 254.4V). Some "shaver sockets", similar to round 2-pin sockets (type C) found in mainland Europe, will supply 110 V, but be careful since they often have a dual mode 110V/240V.

To wire a three phase compressor, you will need a motor starter( three pole contactor) with a motor overload device sized for the motor run current. A single or double pole pressure switch. This example is for 208 volts, coil on starter should be rated for 208 volts. Bring the three phase conductors to the top of the starter from the disconnect and land them in the wire terminals. Bring the three motor leads to the bottom of the starter and land them in the wire terminals. Go back to the top of the starter, land a wire in A phase terminal ( left Hand phase) with the wire that is already there(some starters have provisions for two wires) take this wire to the pressure switch and land on one side of the contact. Land another wire on the other side of the contact and go back to the starter and go the "coil" terminal on the starter. Go back to the top of the starter B phase terminal(center phase) land another wire there and go to the starter overload device terminal. When the pressure switch closes you should have 208 volts present on the starter coil and it should pull in. Once the pressure switch is satisfied the contacts will open and the starter will drop out.