Electronics Engineering

remember the power flow equation

Pm-Pe = Pa(accelerating Power) = 2H/Ws ddelta/dt

1. synchronous generator resistance grounding -

when system suffer any kind of the disturbance which results in Pa accelerating power increases due to increase in Pe electrical power.to keep the balance between Pe and Pm, we reduce the increase amount of Pe electrical power by dissipated in the resister. from above equation we can easily make understand the Pm= Pe (in stability condition)

2. synchronous motor inductance grounding -

Reverse explanation in case of motor

exciton

8086 main application is to evaluate the arithmetic operations in any systems that uses 8086

(110V outlets and 120V outlets are practically the same for this discussion. I will refer to them as 120V. Same with 220V/240V outlets.) For your 120V source I assume you plan to use a standard US 120V 15A outlet. This outlet can provide a maximum of 15A at 120V. This means the outlet can provide 1,800W of power. ( Volts x Amps = Watts ) This is the maximum amount of power this outlet can provide, no more. Also, this is assuming nothing else is drawing power off the circuit this outlet is on. If you try to pull 1800W from an outlet and plug anything else into this circuit, the breaker will blow. Your oven is designed to run off a 50A 240V circuit. Let's say, for argument, it draws 40A at 240V. This means your appliance requires 9,600W of power to run correctly. This is over 5.3 times the absolute maximum amount of power your 120V outlet can provide. There is no way you can run this appliance off this outlet. You have a larger problem here than the voltage difference. Probably not advisable. One of the way transformers are rated is by the maximum wattage the transformer can safely accommodate. Electric ranges (or any appliance used to heat or cool) consume much more energy and require a much higher wattage rating than most other appliances. Unless you know the wattage rating of your transformer and are certain it can safely provide for your electric range, you should NOT use a step-up transformer with your range. Bear in mind that the wattage requirement for any electric range may vary greatly from model to model and varies even more with the demand placed on the range. For example, wattage required by one burner set to 'low' is much less than the same burner set on 'high'. Even more current and wattage is required to run 2 burners, 3 burners, etc... As you can see, there are many variables. The safest situation would assume that the range will always operate at it's maximum capacity (i.e. All burners on and set to high, cooling fans set to their highest level, any light bulbs on, both upper and lower oven heating elements turned on if applicable, any other accessories turned on and operating at their highest setting) and therefore should have a transformer at least 20% higher in capacity than the range at maximum consumption. The maximum wattage rating of the range should be printed on the manufacturers label, the Underwriters Laboratories(UL) label, or in the product installation/owner's manual. If wattage is not specifically given then use this formula to calculate wattage: Watts= Volts x Amps. I think a good question to ask yourself before doing this is, "Am I cool with my entire house burning down?" If your answer is, "No." then you probably need to pay an electrician to run a proper 220/240v line. A modern oven/range combination can easily consume 12,000-15,000 watts. As a comparison, a large hair dryer can consume as much as 2,000 watts. A 15,000 watt step-up transformer easily costs over a thousand bucks. So, unless you happen to have one lying around it's probably cheaper to hire the electrician anyway. One last tip: If the transformer doesn't weigh over 100 pounds, don't even think about it. Transformers are heavy. The bigger, the heavier. Here's a good website: http://www.voltageconverters.com/commercial_transformers.html

Volt (V) = Resistance (R) times Current (I)

therefor

R = V / I

30 Ω = 3V / 0.1A

The amplifier whose output is inphase with it input means if we consider voltage amplification then there is zero phase shift in input and output

Basically, service loads are those applied loads which have not yet been factored. Also known as "working loads"

These are Electronic Design Automation tools. These tools are used to design and implement electronic circuits virtually using a computer. Programming languages like VHDL, Verilog can be used for this purpose.

A large amount of energy, calculated as the voltage difference across the wire, will be expended in that section of wire. This would most likely cause it to glow and/or create a lot of heat, which could possibly melt the wire and break the circuit (this is the principle any fuse is based on - a fuse is a low resistance wire that has a low melting temperature, so a "large" current will cause the fuse to heat excessively, melting the conductor).

A light bulb is exactly this - a "high resistance" wire (or filament), where relatively large current is pushed through a very small cross section of wire, causing it to glow.

There is a thousand milliamps in an amp. So it would be 5.4AH.

"Volts" is electrical pressure applied to a circuit; whereas, "ohms" is electrical resistance to that pressure. One cannot determine ohms from voltage without knowing either the current (in "amps") or power (in "watts"). A normal 120V household circuit can handle a maximum of 20 amps, so using ohm's law of resistance = voltage / current, the minimum resistance required in a 120V household circuit would be 6 ohms. Any less than 6 ohms will cause the circuit breaker to trip.

An ammeter measured how many amperes of current are flowing in an electrical circuit.

a transistor is called a Bi-polar device because in this we use both p-type semiconductor and n-type semiconductor.

In p-type semiconductor the current flows with the help of holes(deficiency of an electron or we can say it as a positive charge).

while in n-type semiconductor the current flows with the help of electrons(negatively charged particles).

so the total current is due to both kind of charge carriers.

that's why it is known as a Bi-polar device.

If you look at the reflection coefficient curve as a function of frequency, it follows a counter-clockwise direction about the Smith chart. You should see a loop, and at the "top" of the loop, that is the oscillation frequency.

They both have in common an open-loop gain greater than one, however. So the curve will be outside the Smith chart.

In a digital circuit probably the best way is with a monostable multivibrator, or one shot timer. The length of the timer should be made to be just a little longer than the bounce time of the switch.

Ans2: My favourite is a 2 input NAND gate with both inputs connected to the switch, but with a small RC delay circuit in one of them.

A: Electricity is not a device but rather a fiscal flow of electrons

Your battery is probably failing and trying to explode.

A Resistor does exactly what the name suggests, it creates resistance.

More precisely, it creates resistance for the flow of electrons, effectively limiting the amount of current flowing through it(and via ohms law, limits voltage).

To answer the question, A resistor isn't an input or output device, it behaves the same way no matter how you turn it and it can be placed on the input of a component(or circuit) aswell as the output.

Might want to change the battery.

LCR meters measure inductance capacitance and resistance

Q requires 2 at once and probably a frequency range you may care about

q meter will probably have two readouts and you may be able to change from Q to power factor