C Programming

One. If you want more, use an array.

Not sure what you mean by class width, but if you mean how do you determine the size of a class, the simplest way is to use the sizeof() operator. The value returned may be equal to or greater than the sum of all its member variables, depending on any adjustments made for memory alignment. If the class contains pointers to memory allocated on the heap, this memory will not be included in the total -- only the size of the pointers to those allocations will be considered.

EDIT: Previous answer does not address the question.

#include<stdio.h>

main()

{

int n,m,i,max;

printf("How many numbers(n) you going to enter:");

scanf("%d",&n);

printf("Enter the numbers:");

scanf("%d",&m);

max=m;

for(i=2;i<=n;i++)

{

scanf("%d",&m);

if(m>max)

max=m;

}

printf("The Largest Number is %d",max);

}

Output:

How many numbers(n) you going to enter:5

Enter the numbers:

25

410

362

5

56

The Largest Number is 410

3 OCTOBER 1954

It is unsafe. In order to use gets() safely, you need to know how many characters you will be reading to ensure your character buffer is large enough:

char buffer[10];

while (gets (buffer) != 0) { ...process buffer... }

The above code has undefined behaviour when the number of characters read is 10 or more (you need one character for the null-terminator). This is because the character buffer, str, decays to a pointer (referencing &str[0]) and the function, gets(), cannot determine the number of characters in a buffer by its pointer alone.

The gets() function was dropped from the C standard in 2011, however some implementations still include it. To avoid the warning, use the fgets() function instead. This allows you to specify the length of your buffer and (when used correctly) prevents buffer overflow.

char buffer[10];

while (fgets (buffer, 10, stdin) != 0) { ...process buffer... }

In real mode far pointers are 32 bit long (segment + offset)

In protected mode 48 bit (16 bit segment + 32 bit offset)

(In 64-bit mode 80 bit (16 nit segment + 64 bit offset) but it's not so useful)

(start)

/a=0 c=0\

\b=0 /

/input a/

/input b/

/input c/

/a>b\ no /b>c\ yes /display b/ -> (a)

\ / \ /

yes no

/a>c\ no /display c/ -> (a)

\ /

yes

/display a/

<- (a)

(end)

No, a unary expression consists of one operand and one operator

empty statement does nothing, 'missing statement' is an error-message from the compiler, eg: { if (x==2) }

corrected version: { if (x==2); }

It makes no sense to convert a list to a tuple given that tuples are specifically intended for collections of heterogeneous types whilst a list is a collection of homogeneous types. If the intent is simply to reduce memory consumption, then converting the list to an array would achieve the exact same result as converting to a tuple.

Code migration is the movement of programming code from one system to another. There are three distinct levels of code migration with increasing complexity, cost and risk. Simple migration involves the movement from language to a newer version. A second, more complicated level of migration involves moving to a different programming language. Migrating to an entirely new platform or operating system is the most complex type of migration.

int main(int argc, char** argv) { char *argument1, *argument2; if (argc < 2) ...{exception}... argument1 = argv[1]; argument2 = argv[2]; } Note: It is up to you to decide if the arguments actually refer to valid filenames. Also, if the filenames contain spaces, this example will not work - you would need to write code to parse (or use library routines) and support quoted filenames.

public static void main(String args){

int counter = 0; //initialize the counter variable to 0

while (counter < 10){ //while the counter variable is less than 10...

counter ++; //increase the counter variable by 1

System.out.println(counter); //print the counter variable

}

}

As integers, within range -128..127 if signed, 0..255 if unsigned.

There is no 'foreach' in C

#include <stdio.h>

main()

{

int m, n, c, d, A[10][10],temp=0;

printf("\nEnter the number of rows and columns for matrix A:\n");

scanf("%d%d", &m, &n);

printf("\nEnter the elements of matrix A:\n");

for ( c = 0 ; c < m ; c++ )

for ( d = 0 ; d < n ; d++ )

scanf("%d", &A[c][d]);

printf("\nMatrix entered is:\n");

for ( c = 0 ; c < m ; c++ )

{

for ( d = 0 ; d < n ; d++ )

printf("%d\t", A[c][d]);

printf("\n");

}

printf("\n\nMaximum element of each row is:\n");

for(c=0;c<m;c++)

{

for(d=0;d<n;d++)

{

if(A[c][d]>temp)

temp=A[c][d];

}

printf("\n\t\tRow %d: %d",c+1,temp); temp=0;

}

temp=A[0][0];

printf("\n\nMinimum element of each coloumn is:\n");

for(c=0;c<n;c++)

{

for(d=0;d<m;d++)

{

if(A[d][c]<temp)

temp=A[d][c];

}

printf("\n\t\tColoumn %d: %d",c+1,temp); temp=A[d][c] ;

}

return 0;

}

mini project is a self made ideal project by using any language.

Sum(All elements in B) - Sum(All elements in A)

Tivo from DirecTV does this. I think the regular Tivo can do this as well.

// Infinite while loop

while(true) {

System.out.println("Still looping...");

}

// More useful while loop to move through all elements in a Queue

Object currentItem;

while((currentItem = queue.poll()) != null) {

System.out.println(currentItem);

}

#include<list>

#include<string>

struct Customer

{

std::string m_name;

std::string m_phone;

Customer (std::string name, std::string phone): m_name(name), m_phone(phone) {}

// ...

};

int main()

{

std::list<Customer> customers;

customers.push_back ("Joe Bloggs", "555 7465");

customers.push_back ("Dan Mann", "555 3458");

// ...

}

If the variable is local to the function it exists until the function returns.

dhfjopdpyp;pg[;ep;ep;