Electronics Engineering

The thyristor functions in such a way that when the anode voltage is greater than the cathode voltage , it is not triggered but only triggers when a gate signal is applied at the gate of the device.

1. Basic salary is 13600( with 3% increment every year. up to 25420)

2. DA is 43% (as on 1-1-2011)

3. HRA 10/20/30% depending up on where they getting postings.

4. plus allowances like Rural, Medical, Special pay, Skill up gradation allowance, Travelling Allowance.

This is gross salary. (Around 22000 with 10% HRA)

And the deductions

1. EPF

2. GSLIS

3. Professional tax - 200 Rs

4. Income tax

5. Ben F - (Around 10 Rs)

and any insurance of the employee which is to be deducted from salary

The voltage-current relationship for a capacitor is i = C dv/dt, where i is the current flowing through, C is the capacitance and dv/dt is the time rate change of the voltage across that capacitor. So, when a capacitor is fully charged, the voltage no longer changes with time (the derivative, dv/dt, is now 0). As can be seen from the equation, the current would therefore be 0. Anything with 0 current flowing through is an open circuit, and can be treated like a resistor with infinite resistance (in models, anyway). Practically speaking, capacitors aren't this perfect, but you will still have an extremely high resistance once fully charged (voltage changes negligibly after charging).

as far as i know ul in uln stands for universal linear and n indicates the temperature range

Electrically small antennas are always narrow-band. The bandwidth of a small antenna has a theoretical maximum defined by the Chu Limit.

We don't use an 'instrument' to covert a.c. to d.c.. Rather, we use a circuit called a 'rectifier'.

It depends on where you are going to use this resistor and what its application going to be. If the circuit you are using can tolerate this then you are fine.

Yes, it will.

To get all the audio voltage from a source to a target without loss you need voltage bridging, that is a relative low output impedance to a higher input impedance. Usualy the input impedance is at least ten times higher then the output impedance.
An input impedance is called also a load impedance or an external impedance.
An output impedance is called also a source impedance or an internal impedance.

Devices, such as amplifiers can't be linear over all input values. At some point they just can't output the required output power. I.e. an amplifier that increases input power by a factor of 10, may not be able to amplify a signal that comes in that is, let's say 10 watts. The point where the device is outputing 1 dB less POWER (which is roughly running at 80%) than it should is the 1 dB compression point. So lets say a 10 watt signal is input, and that the signal should be amplified by a factor of 10, and should output 100 watts. Let's also say the system output power is actually 1 dB down from the expected value and outputting roughly 80 watts, 10 watts is the input 1 dB compression point. Also, look here: http://www.rfcafe.com/references/electrical/p1db.htm

Matrices are mainly used in network analysis to solve problems based on mesh and nodal analysis.

Their applications are also used in network topology to solve problems based on tie set, cut set and incidence matrix.

Men can wear flip flops but usually don't wear them as much as women do as representing and making one sexy is not considered a part of the genderType your answer here...

gearshift, brake pedal, and steering wheel.

A: YES it can to a point but as speed of surges increases the capacitor will start to behave like a coil

Ans. A series L R C in parallel with C' .

No.

No.

Yes, power = voltage x current = 54 x 110 = 5940 watts. But the odd thing is the rated horsepower. I was taught that one horsepower = 746 watts, so 135 hp = 100,000 watts. Are you certain that the pump is rated at 136 horsepower? Or can anyone else address the discrepency? W=volts X amps; therefore W= (110)(54)

zero

I think it might be 20KHz. Q= frequency over bandwidth

The shape of the waveform.

The output waveform will be limited to the difference between the supply and ground (or between the positive and negative supplies).

This causes distortion of the output waveform.

Metals undergo a metallic bonding, meaning when two metals shares their valence electron they undergo metallic bonding. Within the metallic bond, there are enormous amount of free electrons or what we call " SEA OF ELECTRONS, MOBILISE NOT STATIONARY"constantly moving within the lattice. As we know electrons can carry electric and thermal energy through vibrations and pass the energy from each other throughout the lattice or structure. if u put a piece of metal under the sun light, eventually it will get hot and that's because electrons absorb the thermal energy from sun light and gets excited, the same way " when a guy see a hot girls" and starts vibrating.

Telecommunication Engineers are concerned with establishing communication by means of telephones, telegraphs, radar, radio, radio navigational aids, TV, and teleprinters. Important towns, cities, trade centers, harbors and ports are connected with underground cables or radio links. Countries and continents are brought closer by means of fast-emanating, information-carrying communication networks. All this has been made possible by the telecommunication engineer. Telecommunication engineers deal with line and wireless communication, or radio communication. Line communication is handled by telephone/telegraph engineers. The work comprises the installation, supervision, and maintenance of telephone exchanges and telephone lines. The radio communication engineer's work is concerned with the designing, installation, maintenance and periodical testing of broadcasting and telecasting systems and studios, and transmitting and receiving stations.

light up when forward biased