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Electronics Engineering

Electronics Engineering is a branch of engineering that deals with practical applications of electronic components, devices, systems, or equipment. Electronics are devices that operate on low voltage sources, as in electron tubes, transistors, integrated circuits, and printed circuit boards and use electricity as part of its driving force.

24,372 Questions

What are the different types of PLDs?

The different types of PLDs are

  1. ROM
  2. PLA
  3. PAL
  4. SPLD
  5. CPLD
  6. FPGA

Why emitter current flows away from base in NPN transistor?

arrows are shown for conventional current, not electron current.

How does current affect brightness?

When considering standard household electricity, it will likely be a 120V circuit. Ohm's law says current equal voltage divided by resistance (I = V/R). Watts are a unit of power and are I * V.

Assuming a standard lightbulbs of the same general type, higher wattage / hr indicates a greater brightness. With Voltage held constant in this power equation at V=120V, this indicates higher currents will produce a brighter light. Going back to Ohm's law, this is achieved by reducing the resistance.

What is the correct way to install a polarized capacitor?

A polarized capacitor will only allow a voltage drop in one direction, due to the design of the electrolyte. The plus terminal needs to be always more positive than the minus terminal. Any other connection will destroy the capacitor.

Older style can-type capacitors have the case being the common minus terminal. Some terminals are marked only with a red dot. That is the plus terminal. Some are marked with an arrow; in general, that is the minus terminal, but you should read the markings carefully and, if necessary, consult the product specification sheet.

Why is parallel resonant circuit called a rejector circuit?

because at resonance frequency in LRC parallel circuit,impedance is high, so it minimize the current. thus we say its a rejector circuit .

Difference between avalanche and zener breakdown voltage?

"'Zener diode' and 'avalanche diode' are terms often used interchangeably, with the former much more common. Both refer to breakdown of a diode under reverse bias. Specifically, when a diode is reverse biased, very little current flows, and the diode is to a first order approximation an open circuit. As the reverse voltage is increased, though, a point is reached where there is a dramatic increase in current. Equivalently, there is a dramatic reduction in the dynamic resistance (slope of the V-I curve) that can be as low as 1- 2 W in this region.ÝThis voltage is called the reverse breakdown voltage and it is fairly independent of the reverse current flowing.ÝThis property makes it ideal as a voltage reference.Ý "Avalanche breakdown is caused by impact ionization of electron-hole pairs.ÝWhile very little current flows under reverse bias conditions, some current does flow.ÝThe electric field in the depletion region of a diode can be very high. Electron/holes that enter the depletion region undergo a tremendous acceleration.Ý As these accelerated carriers collide with the atoms they can knock electrons from their bonds, creating additional electron/hole pairs and thus additional current.ÝAs these secondary carriers are swept into the depletion region, they too are accelerated and the process repeats itself.ÝThis is akin to an avalanche where a small disturbance causes a whole mountainside of snow to come crashing down.Ý The efficiency of the avalanche effect is characterized by a so-called multiplication factor M that depends on the reverse voltage (Equation 1). Equation 1: Multiplication Factor "Here n is in the range 2 - 6, V is the applied (reverse) voltage, and Vbr is the breakdown voltage.ÝThis is an empirical relationship, as are many of the relationships used to describe both Zener and avalanche breakdown.Ý "Avalanche breakdown occurs in lightly-doped pn-junctions where the depletion region is comparatively long.ÝThe doping density controls the breakdown voltage.ÝThe temperature coefficient of the avalanche mechanism is positive.ÝThat is, as the temperature increases, so does the reverse breakdown voltage.ÝThe magnitude of the temperature coefficient also increases with increasing breakdown voltage. For example, the temperature coefficient of a 8.2 V diode is in the range 3 - 6 mV/K while the temperature coefficient of an 18 V diode is in the range ofÝ 12 - 18 mV/K. "Zener breakdown occurs in heavily doped pn-junctions.ÝThe heavy doping makes the depletion layer extremely thin. So thin, in fact,Ýcarriers canít accelerate enough to cause impact ionization.ÝWith the depletion layer so thin, however, quantum mechanical tunnelingÝ through the layer occurs causing current to flow.ÝThe temperature coefficient of the Zener mechanism is negativeóthe breakdown voltage for a particular diode decreases with increasing temperature.ÝHowever, the temperature coefficient is essentially independent of the rated breakdown voltage, and on the order ofÝ -3 mV/K. "In a 'Zener' diode either or both breakdown mechanisms may be present. At low doping levels and higher voltages the avalanche mechanism dominates while at heavy doping levels and lower voltages the Zener mechanism dominates.ÝAt a certain doping level and around 6 V for Si, both mechanism are present with temperature coefficients that just cancel. It is possible to make Zener diodes with quite small temperature coefficients.Ý "Neither Zener nor avalanche breakdown are inherently destructive in that the crystal lattice is damaged.ÝHowever, the heat generated by the large current flowing can cause damage, so either the current must be limited and/or adequate heat sinking must be supplied."

Why are satellite orbits depicted as sine-wave shapes?

The sine wave represents 360 degrees or a full circle. As the satellite revolves 360 degrees around the earth in its orbit this is how it is represented on a flat surface.

What is the difference between ohms and mohms?

ohms is the SI unit of resistance MHO (siemens) is the SI unit of reciprocal of resistance ie conductance

What is difference between encoder and multiplexer in digital electronics?

An encoder refers to a device that is used to change a signal or data into a code. Whereas a Multiplexer or mux is a device which performs multiplexing or it takes information from more than one channels and outputs into a single channel. Thus a multiplexer is basically a kind of encoder where its function is to combine multiple inputs into one output.

What are 3 factors which affect the magnitude of magnetic force on current-carrying conductors?

Electric current, magnetic field intensity, length of the conductor, angle between the electric current and magnetic field

How hard is it to become a software engineer also how likely are you to get a good job with having a ITT tech BA in software engineer technology?

ITT Tech isn't typically respected in the serious software shops. You might be able to get a job as a support engineer at a small company that just needs someone around. For a serious job at one of the big players you'll need a degree from an accredited college. We turned away quite a few people from the "matchbook school of programming", especially since we typically didn't even take a second look at anyone less than either a Masters or significant experience in the field from other companies. There are quite a few graduates from ITT Tech who are still flipping burgers. Quite a few companies need their own in-house network administrator. That might be a good place to go if you insist on attending ITT Tech.

What is channels to be non-overlapping?

Broadcast media AND OTHER RF COMMUNICATION use electromagnetic waves to send information across distance. An AM radio can use a very narrow frequency to send the information, but FM communications, such as television, your FM radio receiver and most digital signals, use what is called "frequency modulation" to send a signal. In a frequency modulated signal, the base sigal will start at a single frequency. To send information, the signal changes (modulates) the frequency up and/or down from that base frequency. The FCC and other regulating agencies have reserved certain frequencies for specific commercial broadcast use only. A radio signal may not "overlap" or attempt to use the frequency or any part of the frequency that has been assigned to another commercial broadcaster.

What is a artificial dielectric?

The dielectric is composed of "molecules" that are actually perfectly conducting spheres. These have radius R and are in a cubic array with spacing much greater than the radius R. With the application of a voltage, the spheres acquire the positive and negative surface charges on their northern and southern poles required to make their surfaces equipotentials. In so far as the field outside the spheres is concerned, the system is modeled as an array of dipoles, each induced by the applied field.

How do you calculate theoretical yield?

When calculating the theoretical yield of a product within a reaction, the idea is to convert mass reactant --> mass product; in other words, "how many grams of product X will N grams reactant A and N grams reactant B yield (create)?" Whichever mass is the lowest is considered the theoretical yield (in other words, the reactant that produces the least amount of product).

__A + __B --> __X

mass reactant A => mass product X (mass A: mass X)

mass reactant B => mass product X (mass B: mass X)

In order to calculate the theoretical yield, you need to convert the mass of reactant A to the mass of product X AND the mass of reactant B to the mass of product X.

1. Multiply the mass of the reactant by the number of molecules (or moles) X and by the molar mass of X.

2. Divide the above by the molar mass of reactant (which is multiplied by the number of molecules [or moles] of reactant).

Do this for each reactant involved.

- Formula

Mass reactant * # molecules (moles) product X1 * molar mass product X

--------- # molecules (moles) reactant * molar mass reactant

= Mass Product X

- Conversion Factor

Mass reactant * 1 mol reactant * # molecules product X * molar mass product X

-------------- molar mass reactant - # molecules reactant --- 1 mol product X

= Mass Product X

1the # molecules is obtained from the balanced equation. For clarification, I stated # molecules in place of mol; however, on practice problems and in textbook tutorials on how to solve problems in regards to stoichiometry, it is likely it will say mol or moles instead of # molecules.

Ex. Ca(NO3)2 + 2NaF --> CaF2 + 2NaNO3

What is the theoretical yield of CaF2 (product X) when 43.5g Ca(NO3)2 (reactant A) react with 39.5g NaF (reactant B)?

43.5g Ca(NO3)2 * 1 mol Ca(NO3)2 * 1 molecule1 CaF2 * 78.08g CaF2

-------------- 164.1g Ca(NO3)2 ----- 1 molecule1 Ca(NO3)2 - 1 mol NaF

= 22.3g CaF2

36.5g NaF * 1 mol NaF * 1 molecule1 CaF2 * 78.08g CaF2

------------ 41.99g NaF --- 2 molecules1 NaF --- 1 mol CaF2

= 36.7g CaF2

The theoretical yield of CaF2 is 22.3g, as it is the lowest amount of product created. In this case, the limiting reagent (the reactant that produced the least product) is Ca(NO3)2 and the reagent in excess is NaF.

"A chain is only as strong as its weakest link".

How can a relay circuit be used?

A relay circuit is typically a smaller switch or device which drives (opens/closes) an electric switch that is capable of much larger current amounts or a circuit which operates the coil or electronic actuator from one source and uses a separate power source to drive an isolated device.

For the use in electrical engineereing:

Generally speaking, using a relay may involve anything from a very robust approach to an extremely delicate approach. Consider some aspects of a relay. A relay has contacts, arcing and sparking because of back e.m.f from load circuits may damage these contacts and reduce the life span of the device. Some inductive applications might require a low value capacitor across the relay contacts. Just remember that the peak voltage (not rms or AC) of the mains running through the contacts is not more than the rated capacitor voltage value. Do not use polarized capacitors where AC is used. Often a 10nF might make a difference already depending on your back e.m.f of the load obviously. It will also reduce some EMI (electromagnetic interference)

Even if your DC control signal may only see resistance of the coil at the time the coil is on or off. A coil that has inductance and store magnetic energy, the same as any coil will also produce back e.m.f when potential is removed. The collapse of the magnetic field cause a high potential difference, possibly thousands of volts at high frequency. The frequency may in fact be so high that regular diodes or transistors might not stop it. One would recommend a series resistor and use the collector of a NPN transistor with it's emitter to the ground to switch the relay on or off via the base, be sure to have a base resistor to protect the source of the control signal as well as the B-E junction of the transistor, calculation as follow:

Rs = collector series resistor

Rb = is base series resister

beta = current gain for the transistor

Vsource = the control signal voltage minimum that will turn relay on or off

By applying ohm's law we get:

Rc = [Rrelay x (VCC-Vrelay -Vce)]/(Vrelay )

Rb = (Vsource-Vbe)/[(Vrelay/(Relay x Beta)) x 10]

{use factor 10 to compensate for error in beta values}

Don't ever be to comfortable with the fact that there are no electrical connection between the contacts and the coil of a relay. Do not think relays are safe to use with computers or related micro controller devices because they are electrically isolated. It will be a bad mistake!! There are back e.m.f. from the coil aswell as e.m.i from contacts what is induced back into the coil when it has high impedance across it.

It's then recommended to have a fast recovery diode in reverse bias condition across the coil to prevent back e.m.f. of finding its way back home.

This is recommended to protect the driving signal source. Often in small relays using HC or TTL family logic to drive it via a transistor to a transorb or fast recovery diode across the coil may be good enough. Especially if you use it for your self and not to design a heart-lung machine for a hospital.

But if you have micro controllers, computer ports. The damage of a strong back e.m.f may be more than what you bargain for and will probably happen at the worst time in the wrong place. The best is to use a opto-coupler.

The control source will via a series resistor, let say about (330R for a 5V signal) switch an internal LED inside the opto-coupler device on. The light will drive a photo-transistor into forward bias condition. That can be used to drive the transistor that will energize the relay. Since there is no electrical connection between the output pin of the microcontroller that produce the control signal and the relay coil. There is only a one way communication via a light beam. This is by far safer. It creates a typical, 2500V isolation between the robust electrical circuit and it's e.m.f 's, and the sensitive and delicate micro controller or computer circuit environment. A dip in Vcc or pin for less than a millionth of a second dipping with 2 volt or spiking can cause freezing, erratic response or failure of the micro controller. For good electronic design opto-couplers are a very important part of a reliable control system that use micro controllers to control relay output with.

How the DC offsets are generated in the system?

For fault conditions, the DC offset is caused by where the fault occurs on the voltage waveform.

When the fault initially occurs, the voltage can be looked at as an AC waveform superimposed onto an impulse response (A DC wave). The magnitude of the impulse is equivalent to the voltage when the fault initiated (flash over usually occurs near a voltage peak, providing a potentially large DC component).

The inductance of the system (j*w*L) appears as 0 impedance to this DC voltage.

Z (impedance) = R (resistance) + X (inductance), usually X >> R, X = j*w*L

Since X = 0 for the impulse, there is an initial large current since V = I / Z, and Z = R initially.

This current slowly dies off based on the time constant of the circuit, 1/(L*R).

A lot of times you will hear talk of the the DC component being caused by the "X/R ratio". The higher this ratio, the larger the DC component (generally) and the longer the time constant generally is (although this is not always the case).

Similar analysis applies to other causes of DC offset.

What are the examples of sequential circuits with IC?

In general, a sequential circuit is a circuit that depends on a previous state. That means it needs to have some sort of "memory". As the name may suggest, sequence detectors are a good example of a sequential circuit. As bits (1's and 0's) are inputted, it can determine if a certain sequence has been detected. So as each bit gets inputted, it will need to remember it as it gets the next bit. You would need various IC's to create a sequential circuit; most importantly, a memory element of some sort, like a flip-flop.

An electric iron of resistance 20 ohms takes a current of 5A Calculate the heat developed in 30 seconds?

heat developed = 5*5*20*30 = 15000 joules

Answer

With the information supplied, you can only determine the work done (W) by the circuit, not the heat (Q). To do so, you will need to know the mass (m) and specific heat capacity (C) of the conductor, and the temperature-difference between the conductor and its surroundings. The equation you need to do this is:

W - Q = m C (Tf-Ti)

With the information supplied, you can only calculate the work done: W = I2Rt.

Can led works as ac sources?

No. An LED (light emitting diode) allows current to flow in one direction, thus it cannot alternate as is implied by "an AC source".

ANSWER: YES they can. Any diode can work with AC They can work from AC line directly. My overhead light in my kitchen are across 120 AC now for 8 years. But then again I know what I am doing

How do you change a 4 V DC 2 Amp power supply to 4 V DC 200 mA?

As Dave says there is no obvious reason to do so.

However if you put a 200mA fuse or circuit breaker in series between the supply and the load you will protect the load from pulling more than 200mA from the supply should the load malfunction. That way the load is protected from damaging itself (if that was your concern).

Why are two bulbs in a series with a D- cell dim?

They Are Dim Because the d-cell being used does not produce enough energy to light them both