Intel 8086 and 8088

How to write the program un Assembly language to set a password for personal computers?

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0000

0001

0010

0011

0100

0101

Abstract,etc

Accumulator is a general purpose register.it is a 8 bit register in 8085. it stores the temporary results of a current operation doing by 8085.it is also called 'A' register

The 8086/8088 is a CISC based architecture.

You may have a gun on your person in order to protect you, your family, property or anything else.

The 8086 comes in a 40 pin package with 2 ground pins and one power pin; the remaining 37 signal pins every single one is important.

A 32 bit data bus can send out 4 bytes at a time and can take in 2^32 in addressable memory

In 8086 microprocessor the total memory addressing capability is 1 mega bytes. For representing 1 mb there are minimum 4 hex digits are required i.e, 20 bits. but 8086 has fourteen 16-bit registers. That is there are no registers for representing 20 bit address. So,the total memory is divided into 16 logical segments and each segment capacity is 64 kb(kilo bytes). That is 16*64kb=1 mb.So,for representing 64 kb only 16 bit register is sufficient. In 8086 microprocessor the total memory addressing capability is 1 mega bytes. For representing 1 mb there are minimum 4 hex digits are required i.e, 20 bits. but 8086 has fourteen 16-bit registers. That is there are no registers for representing 20 bit address. So,the total memory is divided into 16 logical segments and each segment size is 64 kb(kilo bytes). That is 16*64kb=1 mb.So,for representing 64 kb only 16 bit register is sufficient.

Assembly

Since The vectored Location of RST5.5 lie in Half the location of RST5 and RST6 so it is called RST 5.5(RST 5+1/2 )

Explanation:

Vector Interrrupt Vectored Location

RST 5 0028H

RST 5.5 002CH

RST 6 0030H

Now we add RST5 and RST6 vectored Location's

0028H + 0030H = 0058H

Now Devide The Sum by 2

0058H/2 = 002CH

Which is Vectored Location of RST 5.5.

This You can Check for All other vectored Interrupts TRAP(RST4.5), RST6.5, RST7.5

for 8085 Microprocessor

Thanks .............. S C Patidar

Goto start -> Run and type winmsd.exe. This will bring up system info page. If the string next to Processor is x86, its a 32 bit machine . If the string next to processor is ia64 or AMD64 then its a 64 bit machine.

Source: http://support.microsoft.com/kb/827218

cheers,

Esha

a modified binary code in which sequential binary numbers are represented by expressions that differ only in one bit, to minimize errors.

Macro is a segment of code that needs to be written only once but whose basic structure can be repeated with each reference

Pin 36 on the 8085 is RESET-IN/. There is a bar (/) to indicate that this is a negative logic (low=true) pin. Typically, you connect an RC network to pin 36 (1uF to GND, 75KOhm to Vcc, and small signal diode (1N914) across the capacitor with anode on pin 36) which creates a reset pulse at Vcc power on. The diode is used to force discharge on power off, ensuring a reset sequence when power glitches.

The registers that are pushed and popped from the stack during interrupt servicing depend on the processor architecture and whether or not a specific register is used by the service routine.

Automatically pushed and popped registers include the program counter, flags, and (often) the accumulator. Manually pushed and popped registers include any others that are used, i.e. modified, by the routine. Some programmers push and pop all registers, but that can be unnecessary and wasteful (of time) if some registers are not modified.

addressing modes helps the programmer to store or retrieve the data which is stored in any part of the data memory by addressing mode specified in the program.

The flow of information on the data bus is bi-directional. When status pin S1 is high, it is a read from IO or memory towards the CPU; when S1 is low, it is a write. S1 is present on the 8085. On the 8086/8088 it is inverted and combined with DT and called DT/R-

The source index (SI) register is required for some string (character) operations. In this context the SI is associated with the DS register. The destination index (DI) register is also required for some string operations. In this context the DI is associated with the ES register.

VECTOR INTERRUPT

If the interrupt is assigned to any predefined branching address to its ISR it is termed as vector interrupt.

NON VECTOR INTERRUPT

If the interrupt is not assigned to any predefined branching address to its ISR it is termed as non-vector interrupt.

PRIYAKRISH

2^32 is amount of blocks that address bus could locate. and each blocks is 64bit because data bus has 64 lines. then maximum number of bits stored in memory is (2^32)*64 bit.

By: Mohammad Saghafi

Email: mohammads1364@yahoo.com

data segment

strs db 'madam',0

strr db 5 dup(0)

data ends

code segment

assume cs:code,ds:data,es:data

start:mov ax,data

mov ds,ax

mov es,ax

mov cx,6

lea si,strs

lea di,strr

l1:mov al,strs[si]

mov strr[di],al

inc si

dec di

loop l1

mov cx,6

repe cmpsb

jz l3

mov bx,0000h

jmp l4

l3:mov bx,1111h

l4:int 3h

code ends

end start